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python - 有人在 Matplotlib 中制作了 Parula 颜色图吗?

转载 作者:太空狗 更新时间:2023-10-29 17:19:09 25 4
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我知道有一些 discussion of Matlab copyrighting their new default colormap ,但我想知道是否有勇敢的用户在 Matplotlib 中创建了颜色图。

Viridis很棒,但对于我要尝试做的事情来说有点暗。

最佳答案

如果@tom 提供的链接断开,这里是:

from matplotlib.colors import LinearSegmentedColormap

cm_data = [[0.2081, 0.1663, 0.5292], [0.2116238095, 0.1897809524, 0.5776761905],
[0.212252381, 0.2137714286, 0.6269714286], [0.2081, 0.2386, 0.6770857143],
[0.1959047619, 0.2644571429, 0.7279], [0.1707285714, 0.2919380952,
0.779247619], [0.1252714286, 0.3242428571, 0.8302714286],
[0.0591333333, 0.3598333333, 0.8683333333], [0.0116952381, 0.3875095238,
0.8819571429], [0.0059571429, 0.4086142857, 0.8828428571],
[0.0165142857, 0.4266, 0.8786333333], [0.032852381, 0.4430428571,
0.8719571429], [0.0498142857, 0.4585714286, 0.8640571429],
[0.0629333333, 0.4736904762, 0.8554380952], [0.0722666667, 0.4886666667,
0.8467], [0.0779428571, 0.5039857143, 0.8383714286],
[0.079347619, 0.5200238095, 0.8311809524], [0.0749428571, 0.5375428571,
0.8262714286], [0.0640571429, 0.5569857143, 0.8239571429],
[0.0487714286, 0.5772238095, 0.8228285714], [0.0343428571, 0.5965809524,
0.819852381], [0.0265, 0.6137, 0.8135], [0.0238904762, 0.6286619048,
0.8037619048], [0.0230904762, 0.6417857143, 0.7912666667],
[0.0227714286, 0.6534857143, 0.7767571429], [0.0266619048, 0.6641952381,
0.7607190476], [0.0383714286, 0.6742714286, 0.743552381],
[0.0589714286, 0.6837571429, 0.7253857143],
[0.0843, 0.6928333333, 0.7061666667], [0.1132952381, 0.7015, 0.6858571429],
[0.1452714286, 0.7097571429, 0.6646285714], [0.1801333333, 0.7176571429,
0.6424333333], [0.2178285714, 0.7250428571, 0.6192619048],
[0.2586428571, 0.7317142857, 0.5954285714], [0.3021714286, 0.7376047619,
0.5711857143], [0.3481666667, 0.7424333333, 0.5472666667],
[0.3952571429, 0.7459, 0.5244428571], [0.4420095238, 0.7480809524,
0.5033142857], [0.4871238095, 0.7490619048, 0.4839761905],
[0.5300285714, 0.7491142857, 0.4661142857], [0.5708571429, 0.7485190476,
0.4493904762], [0.609852381, 0.7473142857, 0.4336857143],
[0.6473, 0.7456, 0.4188], [0.6834190476, 0.7434761905, 0.4044333333],
[0.7184095238, 0.7411333333, 0.3904761905],
[0.7524857143, 0.7384, 0.3768142857], [0.7858428571, 0.7355666667,
0.3632714286], [0.8185047619, 0.7327333333, 0.3497904762],
[0.8506571429, 0.7299, 0.3360285714], [0.8824333333, 0.7274333333, 0.3217],
[0.9139333333, 0.7257857143, 0.3062761905], [0.9449571429, 0.7261142857,
0.2886428571], [0.9738952381, 0.7313952381, 0.266647619],
[0.9937714286, 0.7454571429, 0.240347619], [0.9990428571, 0.7653142857,
0.2164142857], [0.9955333333, 0.7860571429, 0.196652381],
[0.988, 0.8066, 0.1793666667], [0.9788571429, 0.8271428571, 0.1633142857],
[0.9697, 0.8481380952, 0.147452381], [0.9625857143, 0.8705142857, 0.1309],
[0.9588714286, 0.8949, 0.1132428571], [0.9598238095, 0.9218333333,
0.0948380952], [0.9661, 0.9514428571, 0.0755333333],
[0.9763, 0.9831, 0.0538]]

parula_map = LinearSegmentedColormap.from_list('parula', cm_data)
# For use of "viscm view"
test_cm = parula_map

if __name__ == "__main__":
import matplotlib.pyplot as plt
import numpy as np

try:
from viscm import viscm
viscm(parula_map)
except ImportError:
print("viscm not found, falling back on simple display")
plt.imshow(np.linspace(0, 100, 256)[None, :], aspect='auto',
cmap=parula_map)
plt.show()

关于python - 有人在 Matplotlib 中制作了 Parula 颜色图吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34859628/

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