python "TypeError: ' numpy.float6 4' object cannot be interpreted as an integer"

Question

import numpy as np

for i in range(len(x)):
    if (np.floor(N[i]/2)==N[i]/2):
        for j in range(N[i]/2):
                pxd[i,j]=x[i]-(delta*j)*np.sin(s[i]*np.pi/180)
                pyd[i,j]=y[i]-(delta*j)*np.cos(s[i]*np.pi/180)

    else:
        for j in range((N[i]-1)/2):
                pxd[i,j]=x[i]-(delta*j)*np.sin(s[i]*np.pi/180)
                pyd[i,j]=y[i]-(delta*j)*np.cos(s[i]*np.pi/180)     

有没有人有解决这个问题的想法？运行这些代码成功地？

Answer 1

N=np.floor(np.divide(l,delta))
...
for j in range(N[i]/2):

N[i]/2 将是一个 float64 但 range() 需要一个整数。只需调用电话即可

for j in range(int(N[i]/2)):