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检测到 c 堆栈粉碎

转载 作者:太空狗 更新时间:2023-10-29 17:14:00 25 4
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我创建了一个文件,在用户想要提供输入时多次打印 Hello, world。

#include <stdio.h>
#include <string.h>
int main() {
char message[10];
int count, i;

strcpy(message, "Hello, world!");

printf("Repeat how many times? ");
scanf("%d", &count);

for(i=0; i < count; i++)
printf("%3d - %s\n", i, message);
}

无论输入什么数字,它总是会导致“stack smash”。这是程序,任何人都可以得出结论为什么要这样做吗?这是检测到堆栈粉碎后发生的“回溯”:

sean@blue:~/programming$ ./a.out
Repeat how many times? 12
0 - Hello, world!
1 - Hello, world!
2 - Hello, world!
3 - Hello, world!
4 - Hello, world!
5 - Hello, world!
6 - Hello, world!
7 - Hello, world!
8 - Hello, world!
9 - Hello, world!
10 - Hello, world!
11 - Hello, world!
*** stack smashing detected ***: ./a.out terminated
======= Backtrace: =========
/lib/i386-linux-gnu/libc.so.6(__fortify_fail+0x45)[0x1f8c75]
/lib/i386-linux-gnu/libc.so.6(+0xe8c27)[0x1f8c27]
./a.out[0x8048524]
/lib/i386-linux-gnu/libc.so.6(__libc_start_main+0xf3)[0x129113]
./a.out[0x80483f1]
======= Memory map: ========
00110000-00288000 r-xp 00000000 08:01 1577912 /lib/i386-linux-gnu/libc-2.13.so
00288000-0028a000 r--p 00178000 08:01 1577912 /lib/i386-linux-gnu/libc-2.13.so
0028a000-0028b000 rw-p 0017a000 08:01 1577912 /lib/i386-linux-gnu/libc-2.13.so
0028b000-0028e000 rw-p 00000000 00:00 0
0036b000-0036c000 r-xp 00000000 00:00 0 [vdso]
00454000-00470000 r-xp 00000000 08:01 1573818 /lib/i386-linux-gnu/libgcc_s.so.1
00470000-00471000 r--p 0001b000 08:01 1573818 /lib/i386-linux-gnu/libgcc_s.so.1
00471000-00472000 rw-p 0001c000 08:01 1573818 /lib/i386-linux-gnu/libgcc_s.so.1
00e7e000-00e9c000 r-xp 00000000 08:01 1573924 /lib/i386-linux-gnu/ld-2.13.so
00e9c000-00e9d000 r--p 0001d000 08:01 1573924 /lib/i386-linux-gnu/ld-2.13.so
00e9d000-00e9e000 rw-p 0001e000 08:01 1573924 /lib/i386-linux-gnu/ld-2.13.so
08048000-08049000 r-xp 00000000 00:14 3801591 /home/sean/programming/a.out
08049000-0804a000 r--p 00000000 00:14 3801591 /home/sean/programming/a.out
0804a000-0804b000 rw-p 00001000 00:14 3801591 /home/sean/programming/a.out
08a9e000-08abf000 rw-p 00000000 00:00 0 [heap]
b77e8000-b77e9000 rw-p 00000000 00:00 0
b77fc000-b7800000 rw-p 00000000 00:00 0
bff87000-bffa8000 rw-p 00000000 00:00 0 [stack]
Aborted

最佳答案

因为 "Hello, world!" 超过了 10 个字符...

关于检测到 c 堆栈粉碎,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9712413/

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