python - 在 Flask-Admin 中处理 MongoEngine 的 DynamicEmbeddedDocument

Question

我有一个问题，我无法找到一个简单的解决方案，将 Flask-Admin 与 MongoEngine 结合使用。我有一个名为 ExerciseResourceContent 的文档类。它有一个“问题”属性，它是一个名为 ExerciseQuestion 的 EmbeddedDocument 的 ListField:

class ExerciseResourceContent(ResourceContent):
    """An exercise with a list of questions."""

    ## Embedded list of questions
    questions = db.ListField(db.EmbeddedDocumentField(ExerciseQuestion))

ExerciseQuestion 文档实际上是一个DynamicEmbeddedDocument:

class ExerciseQuestion(db.DynamicEmbeddedDocument):
    """
    Generic collection, every question type will inherit from this.
    Subclasses should override method "without_correct_answer" in order to define the version sent to clients.
    Subclasses of questions depending on presentation parameters should also override method "with_computed_correct_answer".
    """

    _id = db.ObjectIdField(default=ObjectId)

    ## Question text
    question_text = db.StringField(required=True)

    ## Correct answer (field type depends on question type)
    correct_answer = db.DynamicField()

它可以分为两个类(更多):MultipleAnswerMCQExerciseQuestion 和 UniqueAnswerMCQExerciseQuestion:

class MultipleAnswerMCQExerciseQuestion(ExerciseQuestion):
    """Multiple choice question with several possible answers."""

    ## Propositions
    propositions = db.ListField(db.EmbeddedDocumentField(MultipleAnswerMCQExerciseQuestionProposition))

    ## Correct answer
    correct_answer = db.ListField(db.ObjectIdField())

class UniqueAnswerMCQExerciseQuestion(ExerciseQuestion):
    """Multiple choice question with one possible answer only."""

    ## Propositions
    propositions = db.ListField(db.EmbeddedDocumentField(UniqueAnswerMCQExerciseQuestionProposition))

    ## Correct answer
    correct_answer = db.ObjectIdField()

当我使用 Flask-Admin 创建或编辑 ExerciseResourceContent 时，它会显示一个“问题”列表，我可以从中编辑“Question_text”属性，但看不到“Correct_Answer” “属性，也不是我想要的任何“命题”属性。我在 Flask-Admin 文档中苦苦挣扎，但这似乎是动态内容(字段或文档)的问题，文档中没有任何内容。

谢谢你的帮助

Answer 1

在我看来，您必须为您的模型自定义管理 View 。如果您的模型没有“开箱即用”地正确显示，这是您必须为模型做的一项任务。

在大多数情况下，您不必完全重写 View 。在大多数情况下，自定义内置 View 就足够了。

我没有任何 Flask 开发经验，但您基本上必须继承 ModelView。并将子类注册到管理员

#Customized admin views
class ExerciseQuestionView(ModelView):
 #
 # add customisation code here
 #

class MultipleAnswerMCQExerciseQuestionView(ModelView):
 #
 # add customisation code here
 #

class UniqueAnswerMCQExerciseQuestionView(ModelView):
 #
 # add customisation code here
 #

if __name__ == '__main__':
    # Create admin
    admin = admin.Admin(app, 'Example: MongoEngine')

    # Add admin views
    admin.add_view(ExerciseQuestionView(ExerciseQuestion))
    admin.add_view(MultipleAnswerMCQExerciseQuestionView(MultipleAnswerMCQExerciseQuestion))
    admin.add_view(UniqueAnswerMCQExerciseQuestionView(UniqueAnswerMCQExerciseQuestion))
    #...

无论如何，我认为您应该阅读文档...否则您可能会在这里等待太久...

http://flask-admin.readthedocs.io/en/latest/api/mod_contrib_mongoengine/