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angular - 如何将参数传递给 HttpInterceptor?

转载 作者:太空狗 更新时间:2023-10-29 16:53:18 25 4
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我正在使用 Angular 4.3.1 和 HttpClient。有一个 HttpInterceptor 来设置一些 header 。

在某些 http get 请求中,我需要设置不同的 header 。无论如何,我可以为特定的 HttpRequest 将一些参数传递给此 HttpInterceptor 吗?

@Injectable()
export class MyHttpInterceptor implements HttpInterceptor {

intercept(request: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
if(request.custom.param1) // how can i do this
request = request.clone({
setHeaders: {
'header1': 'xxxxxx'
}
});

else
request = request.clone({
setHeaders: {
'header2': 'yyyyyy'
}
});


return next.handle(request);
}
}

最佳答案

我写了一个拦截器来处理 Http 错误响应。我想允许特定的 Http 调用指示拦截器忽略某些响应状态代码,同时还保留将参数传递给 Http 调用的能力。这是我最终得到的解决方案。 (感谢 Aleksey 在您的回答中提出了最初的想法)。

扩展 HttpParams:

import { HttpParams, HttpParamsOptions  } from '@angular/common/http';

// Cause the HttpErrorInterceptor to ignore certain error response status codes like this:
//
// this.http.get<TypeHere>(`URL_HERE`, {
// params: new InterceptorHttpParams({ statusCodesToIgnore: [400, 401] }, {
// complete: 'false',
// offset: '0',
// limit: '50'
// })
// })

export class InterceptorHttpParams extends HttpParams {
constructor(
public interceptorConfig: { statusCodesToIgnore: number[] },
params?: { [param: string]: string | string[] }
) {
super({ fromObject: params } as HttpParamsOptions);
}
}

拦截器:

intercept(req: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
return next.handle(req).pipe(
tap({
error: (error: any) => {
if (error instanceof HttpErrorResponse) {
const regEx = /^[4-5][0-9][0-9]$/; // 4XX and 5XX status codes

if (regEx.test(error.status.toString())) {
const errorMessage = this.getErrorMessageFromStatus(error.status);

if (!this._shouldIgnoreError(req, error)) {
console.log(`ERROR INTERCEPTOR: ${error.status}`);
this.toastService.alert(errorMessage);
}
}
}
}
})
);
}

// Based on `request.params.interceptorConfig.statusCodesToIgnore`, we can see if we should ignore this error.
_shouldIgnoreError(request: HttpRequest<any>, errorResponse: HttpErrorResponse) {
if (request.params instanceof InterceptorHttpParams
&& Array.isArray(request.params.interceptorConfig.statusCodesToIgnore)
&& request.params.interceptorConfig.statusCodesToIgnore.includes(errorResponse.status)) {

return true;
}

return false;
}

关于angular - 如何将参数传递给 HttpInterceptor?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46075602/

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