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C编程,错误: called object is not a function or function pointer

转载 作者:太空狗 更新时间:2023-10-29 16:38:11 25 4
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<分区>

我正在尝试编写一个实现 Pop 和 Push 功能的程序。问题是,我试图将指向整数 Top 的指针传递给函数,以便这个整数不断变化,但是当我尝试编译时,我总是得到这一行:

**error: called object is not a function or function pointer (*t)--

#include<stdio.h>
#include<stdlib.h>

#define MAX 10
int push(int stac[], int *v, int *t)
{
if((*t) == MAX-1)
{
return(0);
}
else
{
(*t)++;
stac[*t] = *v;
return *v;
}
}

int pop(int stac[], int *t)
{
int popped;
if((*t) == -1)
{
return(0);
}
else
{
popped = stac[*t]
(*t)--;
return popped;
}
}
int main()
{
int stack[MAX];
int value;
int choice;
int decision;
int top;
top = -1;
do{
printf("Enter 1 to push the value\n");
printf("Enter 2 to pop the value\n");
printf("Enter 3 to exit\n");
scanf("%d", &choice);
if(choice == 1)
{
printf("Enter the value to be pushed\n");
scanf("%d", &value);
decision = push(stack, &value, &top);
if(decision == 0)
{
printf("Sorry, but the stack is full\n");
}
else
{
printf("The value which is pushed is: %d\n", decision);
}
}
else if(choice == 2)
{
decision = pop(stack, &top);
if(decision == 0)
{
printf("The stack is empty\n");
}
else
{
printf("The value which is popped is: %d\n", decision);
}

}
}while(choice != 3);
printf("Top is %d\n", top);

}

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