android - 如何在触摸时获取 recyclerView 的项目的位置

Question

我在 DrawerLayout 中有一个 recyclerView。每个行项目都有一个 ImageView 图标和一个 Textbox 文本。我使用 addOnItemTouchListener 来检测用户单击时行项目的位置，以便打开一个新 fragment 。这是我来自 addOnItemTouchListener 的代码:

mRecyclerView.addOnItemTouchListener(new RecyclerView.OnItemTouchListener() {
        @Override
        public boolean onInterceptTouchEvent(RecyclerView rv, MotionEvent e) {
            View item = rv.findChildViewUnder(e.getX(),e.getY()); //finding the view that clicked , using coordinates X and Y
            int position = rv.getChildLayoutPosition(item); //getting the position of the item inside the list
            //Log.d("billy",String.valueOf(position));
            onListViewItemClick(position);
            mDrawer.closeDrawers(); // closing the navigation drawer
            return true;
        }

        @Override
        public void onTouchEvent(RecyclerView rv, MotionEvent e) {

        }

        @Override
        public void onRequestDisallowInterceptTouchEvent(boolean disallowIntercept) {

        }
    });

这是 onListViewItemClick 方法:

public void onListViewItemClick(int position) {
    DrawerItem data = mList.get(position); //Item of the recycler View at specific position
    Bundle lbundle = new Bundle();
    lFragmentManager = getFragmentManager();
    lFragment = lFragmentManager.findFragmentById(R.id.frame_container);
    lFragment = new FragmentHome();
    lbundle.putSerializable("Item", data); // sending to fragment the Item of the Recycler View , which pressed
    lFragment.setArguments(lbundle);
    //To the fragment
    lFragmentManager.beginTransaction().replace(R.id.frame_container ,lFragment ).commit();
}

问题在于，只有当用户单击抽屉导航的行项目的 imageView 时，此实现才有效。如果用户单击 Item 行的 TextView，则变量 position 的值为 -1 。我认为方法 findChildViewUnder(e.getX(), e.getY()) 只返回 imageView 而不是两者。我想要 findChildViewUnder(e.getx(),e.getY()) 返回 viewGroup。

这是定义每一行的 XML 文件 - 抽屉导航的项目:

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
          android:orientation="horizontal"
          android:layout_width="match_parent"
          android:layout_height="match_parent"
          android:background="?android:attr/selectableItemBackground">
<LinearLayout
    android:id="@+id/inner_layout"
    android:layout_width="40dp"
    android:layout_height="wrap_content"
    android:layout_alignBottom="@+id/nv_title"
    android:layout_alignTop="@+id/nv_title"
    android:layout_alignParentLeft="true"
    android:layout_alignParentStart="true">

    <ImageView
        android:layout_width="25dp"
        android:layout_height="25dp"
        android:id="@+id/nv_image"
        android:background="@android:color/transparent"
        android:scaleType="fitXY"
        android:layout_marginLeft="15dp"
        android:layout_gravity="center"/>

</LinearLayout>

<TextView
    android:id="@+id/nv_title"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:paddingLeft="13dp"
    android:minHeight="?android:attr/listPreferredItemHeightSmall"
    android:textAppearance="?android:attr/textAppearanceListItemSmall"
    android:gravity="center_vertical"
    android:layout_centerVertical="true"
    android:layout_alignParentRight="true"
    android:layout_alignParentEnd="true"
    android:layout_toEndOf="@+id/inner_layout"
    android:layout_gravity="center"
    android:singleLine="true"
    android:ellipsize="end"
    android:layout_toRightOf="@+id/inner_layout" />

    </RelativeLayout>

感谢您的帮助!

Answer 1

如果您已经注册了ItemTouchListener，您可以获得如下 View 位置:

public class RecyclerItemClickListener implements RecyclerView.OnItemTouchListener {
    private static final String TAG = RecyclerItemClickListener.class.getSimpleName();

    public void setListener(OnItemClickListener mListener) {
        this.mListener = mListener;
    }

    private OnItemClickListener mListener;

    public RecyclerItemClickListener(Context context) {
        this(context, null);
    }


    GestureDetector mGestureDetector;

    public RecyclerItemClickListener(Context context, OnItemClickListener listener) {
        mListener = listener;
        mGestureDetector = new GestureDetector(context, new GestureDetector.SimpleOnGestureListener() {
            @Override public boolean onSingleTapUp(MotionEvent e) {
                return true;
            }
        });
    }

    @Override public boolean onInterceptTouchEvent(RecyclerView view, MotionEvent e) {
        View childView = view.findChildViewUnder(e.getX(), e.getY());

        if (childView != null && mListener != null && mGestureDetector.onTouchEvent(e)) {
            mListener.onItemClick(view, childView, view.getChildAdapterPosition(childView));
        }
        return false;
    }

    @Override public void onTouchEvent(RecyclerView view, MotionEvent motionEvent) { }

    @Override
    public void onRequestDisallowInterceptTouchEvent(boolean disallowIntercept) {

    }
}

语句 view.getChildAdapterPosition(childView) 是 RecyclerView 的方法，返回触摸 View 在适配器中的位置。