android - 一个信号 |从通知负载获取 URL 并在自定义 WebView 中打开

Question

OneSignal 默认提供在浏览器中打开 URL 的功能。我想发送一个带有通知的 URL，在我创建的 WebView 中打开该 URL。我分享了我收到通知的位置的截图:

 class ExampleNotificationReceivedHandler implements OneSignal.NotificationReceivedHandler {
      @Override
      public void notificationReceived(OSNotification notification) {
        JSONObject data = notification.payload.additionalData;
        String customKey;

        if (data != null) {
          customKey = data.optString("customkey", null);
          if (customKey != null)
            Log.i("OneSignalExample", "customkey set with value: " + customKey);
        }
      }
    }

我不确定如何在打开的推送中检索 URL 并在 WebView 中打开它。

Answer 1

SlashG 的回答对我很有帮助。这是我的实现...我在我的应用程序类 onCreate()

中添加了这段代码

OneSignal.startInit(this).setNotificationOpenedHandler(new OneSignal.NotificationOpenedHandler() {
            @Override
            public void notificationOpened(OSNotificationOpenResult result) {

                String launchURL = result.notification.payload.launchURL;

                if (launchURL != null) {
                    Log.d(Const.DEBUG, "Launch URL: " + launchURL);

                    Intent intent = new Intent(getApplicationContext(), WebViewActivity.class);
                    intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT | Intent.FLAG_ACTIVITY_NEW_TASK);
                    intent.putExtra("url", launchURL);
                    startActivity(intent);

                } else {
                    Log.d(Const.DEBUG, "Launch URL not found");

                    Intent intent = new Intent(getApplicationContext(), SplashActivity.class);
                    intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT | Intent.FLAG_ACTIVITY_NEW_TASK);
                    startActivity(intent);
                }
            }
        }).init();