android - 如何获取 RTSP URL？

Question

我正在开发一个包含视频 View 的应用程序，这是我的问题

1. 当我加载正常 url 时，Youtube 的 URL 不起作用
2. 如何将上述 URL 转换为 RTSP？
3. 我用过的链接http://www.youtube.com/watch?v=8mIOkkkA2jA

我试过的代码:

VideoView videoView = (VideoView) findViewById(R.id.VideoView); 
MediaController mediaController = new MediaController(this); 
mediaController.setAnchorView(videoView); Uri video = Uri.parse("youtube.com/watch?v=8mIOkkkA2jA";); 
videoView.setMediaController(mediaController); 
videoView.setVideoURI(video); 
videoView.start();

请大家解释一下如何实现这一目标？提前致谢!!!!!!

Answer 1

注意:仅适用于 android 手机(不适用于平板电脑)

private class YourAsyncTask extends AsyncTask<Void, Void, Void>
    {
        ProgressDialog progressDialog;

        @Override
        protected void onPreExecute()
        {
            super.onPreExecute();
            progressDialog = ProgressDialog.show(AlertDetail.this, "", "Loading Video wait...", true);
        }

        @Override
        protected Void doInBackground(Void... params)
        {
            try
            {
                String url = "http://www.youtube.com/watch?v=1FJHYqE0RDg";
                videoUrl = getUrlVideoRTSP(url);
                Log.e("Video url for playing=========>>>>>", videoUrl);
            }
            catch (Exception e)
            {
                Log.e("Login Soap Calling in Exception", e.toString());
            }
            return null;
        }

        @Override
        protected void onPostExecute(Void result)
        {
            super.onPostExecute(result);
            progressDialog.dismiss();
/*
            videoView.setVideoURI(Uri.parse("rtsp://v4.cache1.c.youtube.com/CiILENy73wIaGQk4RDShYkdS1BMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp"));
            videoView.setMediaController(new MediaController(AlertDetail.this));
            videoView.requestFocus();
            videoView.start();*/            
            videoView.setVideoURI(Uri.parse(videoUrl));
            MediaController mc = new MediaController(AlertDetail.this);
            videoView.setMediaController(mc);
            videoView.requestFocus();
            videoView.start();          
            mc.show();
        }

    }

public static String getUrlVideoRTSP(String urlYoutube)
    {
        try
        {
            String gdy = "http://gdata.youtube.com/feeds/api/videos/";
            DocumentBuilder documentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
            String id = extractYoutubeId(urlYoutube);
            URL url = new URL(gdy + id);
            HttpURLConnection connection = (HttpURLConnection) url.openConnection();
            Document doc = documentBuilder.parse(connection.getInputStream());
            Element el = doc.getDocumentElement();
            NodeList list = el.getElementsByTagName("media:content");///media:content
            String cursor = urlYoutube;
            for(int i = 0; i < list.getLength(); i++)
            {
                Node node = list.item(i);
                if(node != null)
                {
                    NamedNodeMap nodeMap = node.getAttributes();
                    HashMap<String, String> maps = new HashMap<String, String>();
                    for (int j = 0; j < nodeMap.getLength(); j++)
                    {
                        Attr att = (Attr) nodeMap.item(j);
                        maps.put(att.getName(), att.getValue());
                    }
                    if(maps.containsKey("yt:format"))
                    {
                        String f = maps.get("yt:format");
                        if (maps.containsKey("url"))
                        {
                            cursor = maps.get("url");
                        }
                        if (f.equals("1"))
                            return cursor;
                    }
                }
            }
            return cursor;
        }
        catch(Exception ex)
        {
            Log.e("Get Url Video RTSP Exception======>>", ex.toString());
        }
        return urlYoutube;

    }

protected static String extractYoutubeId(String url) throws MalformedURLException
    {
        String id = null;
        try
        {
            String query = new URL(url).getQuery();
            if (query != null)
            {
                String[] param = query.split("&");
                for (String row : param)
                {
                    String[] param1 = row.split("=");
                    if (param1[0].equals("v"))
                    {
                        id = param1[1];
                    }
                }
            }
            else
            {
                if(url.contains("embed"))
                {
                    id = url.substring(url.lastIndexOf("/") + 1);
                }
            }
        }
        catch(Exception ex)
        {
            Log.e("Exception", ex.toString());
        }
        return id;
    }