c - 初始化指向 const 字符串的指针数组结构

Question

我正在寻找 C 中的数据结构，它允许我使用压缩语法声明和初始化数百个字符串，如下所示，这在 C11 中可行吗？

#include <stdio.h>

enum {ENGLISH, SPANISH, FRENCH, NUM_LANGUAGES};

struct language_string =
{
    const char* language_hello[NUM_LANGUAGES]   = {"Hello",     "Hola",     "Bonjour"};
    const char* language_goodbye[NUM_LANGUAGES] = {"Goodbye",   "Adiós",    "Au revoir"};
};

void foo(void)
{
    printf(language_string.language_hello[ENGLISH]);        // print "Hello"
}

编辑:我已经意识到，在头文件中，我可以公开所有字符串，而无需将它们包装在结构中或将它们外部化，并实现主要目的，每个字符串一行:

const char*  language_hello[NUM_LANGUAGES]   = {"Hello",   "Hola",  "Bonjour"};
const char*  language_goodbye[NUM_LANGUAGES] = {"Goodbye", "Adiós", "Au revoir"};

Answer 1

你所拥有的已经差不多是对的了。但是，您不能像那样交错声明和初始化。这是一个更正的示例:

struct
{
    const char* language_hello[NUM_LANGUAGES];
    const char* language_goodbye[NUM_LANGUAGES]; 
} language_string = {
    {"Hello",     "Hola",     "Bonjour"},
    {"Goodbye",   "Adiós",    "Au revoir"}
};