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android - 尝试读取 httpResponse 时套接字关闭异常

转载 作者:太空狗 更新时间:2023-10-29 16:04:39 26 4
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我有一种方法可以连接以将发布数据发送到网络服务并获得如下响应:

public HttpResponse sendXMLToURL(String url, String xml, String httpClientInstanceName) throws IOException {
HttpResponse response = null;

AndroidHttpClient httpClient = AndroidHttpClient.newInstance(httpClientInstanceName);
HttpPost post = new HttpPost(url);

StringEntity str = new StringEntity(xml);
str.setContentType("text/xml");
post.setEntity(str);

response = httpClient.execute(post);

if (post != null){
post.abort();
}
if (httpClient !=null){
httpClient.close();
}

return response;
}

然后,在我的 fragment 的 AsyncTask 中,我尝试使用 getEntity() 读取响应:

HttpResponse response = xmlUtil.sendXMLToURL("url", dataXML, "getList");

//Check if the request was sent successfully
if (response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
// Parse result to check success
responseText = EntityUtils.toString(response.getEntity());

if (!xmlParser.checkForSuccess(responseText, getActivity())){
//If webservice response is error
///TODO: Error management
return false;
}
}

当我到达那条线时:

responseText = EntityUtils.toString(response.getEntity());

我得到一个异常:java.net.SocketException: Socket closed

这种行为不会一直发生,也许每隔一段时间就会发生。

最佳答案

随便写

HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(your url);
HttpResponse response = client.execute(post);

它应该可以工作。无需编写会造成混淆的代码。

关于android - 尝试读取 httpResponse 时套接字关闭异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19165420/

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