html - 单击透明区域下方的链接(三 Angular 形或多边形链接)

Question

检查以下代码: http://jsfiddle.net/q8Ycz

<div style="background-color: red; width: 200px;" onclick="alert('behind')"> 
  <div><a href="test">test test test test test test test test test test test</a></div>
  <div><a href="test">test test test test test test test test test test test</a></div>
  <div><a href="test">test test test test test test test test test test test</a></div>
  <div><a href="test">test test test test test test test test test test test</a></div>
  <div><a href="test">test test test test test test test test test test test</a></div>
  <div><a href="test">test test test test test test test test test test test</a></div>
  <div><a href="test">test test test test test test test test test test test</a></div>
  <div><a href="test">test test test test test test test test test test test</a></div>
  <svg xmlns="http://www.w3.org/2000/svg" version="1.1" height="190" style="position: absolute; top: 0; left: 0;">
    <polygon onclick="alert('hello')" points="100,10 40,180 190,60 10,60 160,180" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:evenodd;">
  </svg> 
  </div> 

我有一个 svg 多边形。有什么方法可以启用星形透明部分下的链接。

Answer 1

您可以使用指针事件。添加到 SVG 标签:

pointer-events:none

和多边形标签:

pointer-events:fill

请参阅 http://jsfiddle.net/poselab/yPWxQ/ 中的以下示例

更多信息:

• https://developer.mozilla.org/en-US/docs/Web/CSS/pointer-events
• http://www.w3.org/TR/pointerevents/