gpt4 book ai didi

php - 如何在 table 内制作菱形图案/形状(星号)? (html + php)

转载 作者:太空狗 更新时间:2023-10-29 15:54:02 25 4
gpt4 key购买 nike

我必须在表格内使用 for 循环制作一个菱形星号。 它必须有“空白” <td>星号前后的空格移动并使其看起来居中,所以它看起来像钻石。我怎么做? (我在 HTML 代码中使用了 PHP。)

没有 <tr> 的代码和 <td>标签,它看起来像一颗钻石,因为它居中对齐:

<center>
<?php
echo "<table border = 1>";

// loop for the pyramid

for($i = 1; $i <= 10; $i += 2) {
for($j = 1; $j <= $i; $j++) {
echo "* ";
}
echo "<br />";
}

// loop for the inverted pyramid, so it looks like a diamond

for($i = 7; $i >= 1; $i -= 2) {
for($j = 1; $j <= $i; $j++) {
echo "* ";
}
echo "<br />";
}

echo "</table>";
?>
</center>

代码为 <tr><td>标签,需要“空格”才能使其看起来像居中对齐:

<?php
echo "<table border = 1>";

// loop for the pyramid

echo "<tr>";
for($i = 1; $i <= 10; $i += 2) {
echo "<tr>";
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
echo "</tr>";
}
echo "</tr>";

// loop for the inverted pyramid, so it looks like a diamond

for($i = 7; $i >= 1; $i -= 2) {
echo "<tr>";
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
echo "<br />";
echo "</tr>";
}

echo "</table>";
?>

求助!

最佳答案

这是您的解决方案的新代码。我添加了将空白 td 向前和向后放置到 *

的逻辑
<?php
echo "<table border = 1>";

// loop for the pyramid

echo "<tr>";
$max = $initAmount = 10;
for($i = 1; $i <= $initAmount; $i += 2) {
$max = $max -2;

$halfTD = (int)$max/2;
echo "<tr>";
for($b = 1; $b <= $halfTD; $b++){
echo "<td></td>";
}
for($j = 1; $j <= $i; $j++) {


echo "<td>* </td>";
}
for($b = 1; $b <= $halfTD; $b++){
echo "<td></td>";
}
echo "</tr>";
}
echo "</tr>";

// loop for the inverted pyramid, so it looks like a diamond
$max = $initAmount = 10;
for($i = 7; $i >= 1; $i -= 2) {
$max = $max -2;
$diff = $initAmount - $max;
$blankTd = $diff/2;

echo "<tr>";
for($b = 1 ; $b <= $blankTd; $b++){
echo "<td></td>";
}
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
for($b = 1 ; $b <= $blankTd; $b++){
echo "<td></td>";
}
echo "</tr>";
}

echo "</table>";
?>

关于php - 如何在 table 内制作菱形图案/形状(星号)? (html + php),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40804926/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com