java - ArrayList 无法转换为 int

Question

这可能是一个简单的问题，我也看到过类似的问题，但我看不出他们的回答如何适用于我的，所以我提前道歉，但我收到了这个错误:
不兼容的类型:ArrayList 无法转换为 int

这是一项作业，我不确定自己做错了什么。

这是我的代码:

package com.example.android.miwok;

import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.widget.ListView;

import java.util.ArrayList;

public class NumbersActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_numbers);

        // Create a list of words
        ArrayList<Word> words = new ArrayList<Word>();
        words.add(new Word("one", "lutti"));
        words.add(new Word("two", "otiiko"));
        words.add(new Word("three", "tolookosu"));
        words.add(new Word("four", "oyyisa"));
        words.add(new Word("five", "massokka"));
        words.add(new Word("six", "temmokka"));
        words.add(new Word("seven", "kenekaku"));
        words.add(new Word("eight", "kawinta"));
        words.add(new Word("nine", "wo’e"));
        words.add(new Word("ten", "na’aacha"));

        // Create an {@link WordAdapter}, whose data source is a list of {@link Word}s. The
        // adapter knows how to create list items for each item in the list.
        WordAdapter adapter = new WordAdapter(this, words);

        // Find the {@link ListView} object in the view hierarchy of the {@link Activity}.
        // There should be a {@link ListView} with the view ID called list, which is declared in the
        // activity_numbers.xml layout file.
        ListView listView = (ListView) findViewById(R.id.list);

        // Make the {@link ListView} use the {@link WordAdapter} we created above, so that the
        // {@link ListView} will display list items for each {@link Word} in the list.
        listView.setAdapter(adapter);
    }

我在这一行收到错误:

WordAdapter adapter = new WordAdapter(this, words);

这是我的适配器代码:

package com.example.android.miwok;

        import android.content.Context;
        import android.view.LayoutInflater;
        import android.view.View;
        import android.view.ViewGroup;
        import android.widget.ArrayAdapter;

        import java.util.ArrayList;

/**
 * Created by danle on 7/25/2016.
 */
public class WordAdapter extends ArrayAdapter<Word> {
    public WordAdapter(Context context, int resource) {
        super(context, resource);
    }

    public WordAdapter(NumbersActivity context, int resource, ArrayList<Word> words) {
        super(context, resource, words);
    }




    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View listItemView = convertView;
        if (listItemView == null) {
            listItemView = LayoutInflater.from(getContext()).inflate(
                    R.layout.list_item, parent, false);
        }
        return listItemView;
    }
}

Answer 1

问题是你的第二个构造函数。 ArrayAdapter 没有 super 构造函数只需要一个上下文和一个 ArrayList<Word> .所以 super 正在调用 (Context, int)并尝试将单词转换为整数资源。

public WordAdapter(NumbersActivity context, ArrayList<Word> words) {
    super(context, words);
}

你的构造函数应该是

public WordAdapter(NumbersActivity context, int resource, ArrayList<Word> words) {
    super(context, resource, words);
}