android - Vibrator.vibrate() 抛出 ArrayIndexOutOfBoundsException

Question

我使用以下代码 fragment 以特定模式振动手机，但它抛出 ArrayIndexOutOfBoundsException。

vibrator.vibrate(new long[] { selectedDuration, CONSTANT_DELAY }, REPEAT); 

但是

vibrator.vibrate(VIBRATE_DURATION);

工作正常。有什么指点吗？

Answer 1

文档说:

If you want to repeat, pass the index into the pattern at which to start the repeat.

表示在您的情况下 REPEAT 只允许为 0 或 1。

这是实现:

public void vibrate(long[] pattern, int repeat)
{
    // catch this here because the server will do nothing.  pattern may
    // not be null, let that be checked, because the server will drop it
    // anyway
    if (repeat < pattern.length) {
        try {
            mService.vibratePattern(pattern, repeat, mToken);
        } catch (RemoteException e) {
        }
    } else {
        throw new ArrayIndexOutOfBoundsException();
    }
}