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java - 使用 HttpClient POST 提交表单并上传

转载 作者:太空狗 更新时间:2023-10-29 15:42:16 24 4
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我有一个看起来像这样的 html 表单:

<div class="field>
<input id="product_name" name="product[name]" size="30" type="text"/>
</div>

<div class="field>
<input id="product_picture" name="product[picture]" size="30" type="file"/>
</div>

我想编写一个 Java 模块来自动创建产品。这是我已有的:

HttpHost host = new HttpHost("localhost", 3000, "http");
HttpPost httpPost = new HttpPost("/products");
List<BasicNameValuePair> data = new ArrayList<BasicNameValuePair>();
data.add(new BasicNameValuePair("product[name]", "Product1"));
UrlEncodedFormEntity entity = new UrlEncodedFormEntity(data, "UTF-8");
httpPost.setEntity(entity);
HttpResponse postResponse = httpClient.execute(host, httpPost);

这工作正常,它能够创建名为“Product1”的新产品。但我不知道如何处理上传部分。我想要这样的东西:

data.add(new BasicNameValuePair("product[name]", "Product1"));

但不是“Product1”,而是一个文件。我阅读了 HttpClient 的文档,据说只有字符串。

有谁知道如何处理上传部分?

最佳答案

依赖关系:

<dependency>
<groupid>org.apache.httpcomponents</groupid>
<artifactid>httpclient</artifactid>
<version>4.0.1</version>
</dependency>

<dependency>
<groupid>org.apache.httpcomponents</groupid>
<artifactid>httpmime</artifactid>
<version>4.0.1</version>
</dependency>

代码:[棘手的部分是使用 MultipartEntity ]

HttpClient client = new DefaultHttpClient();
client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION,HttpVersion.HTTP_1_1);
HttpPost post = new HttpPost( url );
MultipartEntity entity = new MultipartEntity( HttpMultipartMode.BROWSER_COMPATIBLE );
// For File parameters
entity.addPart( paramName, new FileBody((( File ) paramValue ), "application/zip" ));
// For usual String parameters
entity.addPart( paramName, new StringBody( paramValue.toString(), "text/plain", Charset.forName( "UTF-8" )));
post.setEntity( entity );
// Here we go!
String response = EntityUtils.toString( client.execute( post ).getEntity(), "UTF-8" );
client.getConnectionManager().shutdown();

关于java - 使用 HttpClient POST 提交表单并上传,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11546609/

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