android - com.google.android.gms.common.api.ApiException : 12500

Question

这是我的第一次尝试....试图找出最近 2 天的问题。我正在尝试将 google 登录集成到 android 应用程序中，但是如下所示:com.google.android.gms.common.api.ApiException: 12500

遵循以下代码: https://firebase.google.com/docs/auth/android/google-signin

• 确保开发控制台中存在 oauth 客户端 ID，并按照其他帖子中的建议使用来自 ~/.android/debug.keystore 的正确 SHA-1 指纹。

• 在应用级别使用最新的播放服务 49 和 build.gradle:实现 'com.google.android.gms:play-services-auth:16.0.1'

• 在项目级 build.gradle 中使用以下内容:

buildscript {//... dependencies {//... classpath 'com.google.gms:google-services:4.1.0'//google-services 插件 }

public class SignUpActivity extends AppCompatActivity {

private GoogleSignInClient gsc;

private FirebaseAuth firebaseAuth;
  @Override
  protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_signup);
    GoogleSignInOptions gso = new GoogleSignInOptions
      .Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
      .requestIdToken(String.valueOf(R.string.gplus_api_client_id))
      .requestEmail()
      .build();

    gsc = GoogleSignIn.getClient(this, gso);

    //Initialize firebase authentication
    firebaseAuth = FirebaseAuth.getInstance();
  }


  @Override
  public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    // Result returned from launching the Intent from GoogleSignInClient.getSignInIntent(...);
    if (requestCode == RC_SIGN_IN) {
      // The Task returned from this call is always completed, no need to attach
      // a listener.
      Task < GoogleSignInAccount > task = GoogleSignIn.getSignedInAccountFromIntent(data);

      handleSignInResult(task);
    }
  }
  private void handleSignInResult(Task < GoogleSignInAccount > completedTask) {
    try {
      //Sign in Successful
      GoogleSignInAccount account = completedTask.getResult(ApiException.class);
      Log.w("SignUpActivity/handleSignInResult", "Trying signing in with Google...  " + account);
      firebaseAuthWithGoogle(account);

      // Signed in successfully, show authenticated UI.

      // Log.w("SignUpActivity/handleSignInResult", "Google sign in successful for account " + account);

    } catch (ApiException e) {
      // The ApiException status code indicates the detailed failure reason.
      // Please refer to the GoogleSignInStatusCodes class reference for more information.
      Log.w("SignUpActivity/handleSignInResult", "Google sign in failed with exception: " + e);
    }
  }

  private void firebaseAuthWithGoogle(GoogleSignInAccount account) {
    Log.i("SignUpActivity/firebaseAuthWithGoogle", "Signed in as : " + account.getId());

    AuthCredential credential = GoogleAuthProvider.getCredential(account.getIdToken(), null);

    firebaseAuth.signInWithCredential(credential)
      .addOnCompleteListener(this, new OnCompleteListener < AuthResult > () {
        @Override
        public void onComplete(@NonNull Task < AuthResult > task) {
          if (task.isSuccessful()) {
            FirebaseUser user = firebaseAuth.getCurrentUser();
            Log.i("SignUpActivity/firebaseAuthWithGoogle", "Sign in successful for user : " + user);
          } else {
            Log.e("SignUpActivity/firebaseAuthWithGoogle", "User Authentication failed.");
            Snackbar.make(findViewById(R.id.view_signup), "Authentication failed.", Snackbar.LENGTH_SHORT);
          }
        }
      });
  }
}

Answer 1

我有这个问题。并且已经解决了。 SHA1 debug 和 relase 都已添加到 Firebase 控制台，但仍然无法正常工作。我也尝试只进行 SHA1 调试，但仍然没有用。经过这么多次尝试和错误后，我通过从凭据菜单中完成“oAuth 同意屏幕”的信息解决了它，步骤如下:

1. 登录到 Google Console Cloud
2. 选择与当前 Firebase 项目相关的当前项目
3. 导航到 API 和服务
4. 点击凭据菜单
5. 点击“oAuth 同意屏幕”
6. 添加应用程序 Logo 、应用程序主页链接和应用程序隐私政策链接。要添加这两个链接，您只需从“oAuth 同意屏幕”的授权域部分复制并粘贴，例如:your-app-abc123.firebaseapp.com