gpt4 book ai didi

c - 多个管道和进程

转载 作者:太空狗 更新时间:2023-10-29 15:35:31 24 4
gpt4 key购买 nike

我正在尝试与子进程通信并使它们对列表的一部分进行排序。我的问题是子进程读取所有内容但之后什么也不做。

int main(int argc, char *argv[]){
int i;
int num_children;
pid_t pid;

num_children= 3;

int fd[num_children][2]; //PIPES

for (i=0; i<num_children; i++)
{
if (pipe(fd[i]) == -1)
{
printf("couldnt create the pipe\n");
exit(EXIT_FAILURE);
}
}


for (i=0; i<num_children; i++)
{
pid = fork();
if (pid == -1)
{
printf("couldnt create child process %i\n",i);
exit(EXIT_FAILURE);
}

if (pid == 0)
{ //this is child process
close(fd[i][1]); //closing fd[1] the write end of the pipe
int received;
node *list = NULL;
while ( read(fd[i][0], &received, sizeof(int)) > 0)
{
list = insert(list, received);
printf("Process %i got the number: %i\n",i,received); //this part is working perfect
}

printf("Im process %i here is my list: \n",i); //i couldnt get any output from here
printList(list);

close(fd[i][0]);
exit(EXIT_SUCCESS);
}
}


for (i=0; i<num_children; i++) //closing the read end of pipe for parent
{
close(fd[i][0]);
}

int number;
int mod;
FILE *fileIn = fopen ("<file directory>","r");
while(fscanf(fileIn, "%i", &number)>=0)
{
mod = number % num_children;
write(fd[mod][1], &number, sizeof(int));
}

for (int i=0; i<num_children; i++)
{
if(close(fd[i][1])==0)
{
printf("cant close the pipe");
//tried to catch errors, but pipes are closing with no problem i think
}
}

return 0;

我试图查看子进程是否在 while(read) 循环中等待,但是当我关闭来自父进程的管道写入端时,它们应该离开循环。

最佳答案

您可能认为某些特定的 pipe[2] 由父进程共享,并且是各自的子进程。没错……但是它也被您在此过程中创建的所有其他子进程共享 - 因为它是打开的,所以其他子进程也会在打开时继承它。

在你的 child pid 检查开始时这样做对我有用:

if (pid == 0) {
int j;
for (j = 0; j < num_children; j++) {
if (j != i) {
close(fd[j][0]);
close(fd[j][1]);
}
}
...
}

关于c - 多个管道和进程,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28719343/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com