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php - 使用 PHP 通过 Android 从 MySQL 插入和接收数据

转载 作者:太空狗 更新时间:2023-10-29 15:09:21 28 4
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我在运行此应用程序时遇到类似错误。“解析数据 org.json.JSONException 时出错:值

这是我的register_user.java

package com.iwantnew.www;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.app.ProgressDialog;
import android.content.Intent;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

public class register_user extends Activity{
// Progress Dialog
private ProgressDialog pDialog;
JSONParser jsonParser = new JSONParser();
EditText signup_username;
EditText signup_email;
EditText signup_password;
Button registerBtn;
TextView registerErrorMsg;

// url to create new product
private static String url_create_users = "http://10.0.2.2/http://10.0.2.2/android_iwant/signup_success.php";
// JSON Node names
private static final String TAG_SUCCESS = "success";

public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.signup_form);
// Edit Text
signup_username = (EditText) findViewById(R.id.signup_username);
signup_email = (EditText) findViewById(R.id.signup_email);
signup_password = (EditText) findViewById(R.id.signup_password);
registerBtn = (Button) findViewById(R.id.regiserBtn);

// button click event
registerBtn.setOnClickListener(new View.OnClickListener() {

@Override
public void onClick(View view) {
// creating new product in background thread
new CreateNewUser().execute();
}
});

}
class CreateNewUser extends AsyncTask<String, String, String> {

/**
* Before starting background thread Show Progress Dialog
* */
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(register_user.this);
pDialog.setMessage("Creating Users..");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}

/**
* Creating product
* */
protected String doInBackground(String... args) {
/*String username = signup_username.getText().toString();
String email = signup_email.getText().toString();
String password = signup_password.getText().toString();*/

//Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", signup_username.getText().toString()));
params.add(new BasicNameValuePair("email",signup_email.getText().toString()));
params.add(new BasicNameValuePair("password", signup_password.getText().toString()));

// getting JSON Object
// Note that create product url accepts POST method
JSONObject json = jsonParser.makeHttpRequest(url_create_users,
"POST", params);

// check log cat fro response
Log.d("Create Response", json.toString());

// check for success tag
try {
int success = json.getInt(TAG_SUCCESS);

if (success == 1) {
// successfully created users
Intent i = new Intent(getApplicationContext(), MainActivity.class);
startActivity(i);

// closing this screen
finish();
} else {
// failed to create users

}
} catch (JSONException e) {
e.printStackTrace();
}

return null;
}

/**
* After completing background task Dismiss the progress dialog
* **/
protected void onPostExecute(String file_url) {
// dismiss the dialog once done
pDialog.dismiss();
}

}

}

这是 JSONParser.java。这是android的数据解析类

package com.iwantnew.www;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.util.List;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.utils.URLEncodedUtils;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;

import android.util.Log;

public class JSONParser {

static InputStream is = null;
static JSONObject jObj = null;
static String json = "";

// constructor
public JSONParser() {

}

// function get json from url
// by making HTTP POST or GET method
public JSONObject makeHttpRequest(String url, String method,
List<NameValuePair> params) {

// Making HTTP request
try {

// check for request method
if(method == "POST"){
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));

HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();

}else if(method == "GET"){
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);

HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}

} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}

// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}

// return JSON String
return jObj;

}
}

这是PHP代码(signup_success.php)

<?php
// array for JSON response
$response = array();
if(isset($_POST['username']) && isset($_POST['email']) && isset($_POST['password'])){
$username = $_POST['username'];
$email = $_POST['email'];
$password = $_POST['password'];

// include db connect class
require_once __DIR__ . '/db_connect.php';


// connecting to db
$db = new DB_CONNECT();

$uuid = uniqid('', true);
$hash = $this->hashSSHA($password);
$encrypted_password = $hash["encrypted"]; // encrypted password
$salt = $hash["salt"]; // salt
$result = mysql_query("INSERT INTO users(unique_id, name, email, encrypted_password, salt, created_at) VALUES('$uuid', '$username', '$email', '$encrypted_password', '$salt', NOW())");
// check for successful store
if ($result) {
// get user details
$uid = mysql_insert_id(); // last inserted id
$result = mysql_query("SELECT * FROM users WHERE uid = $uid");
// return user details
return mysql_fetch_array($result);
} else {
return false;
}

$result = mysql_query("INSERT INTO users(name,email,password) VALUES ('$username','$email,$password')");
// check if row inserted or not
if ($result) {
// successfully inserted into database
$response["success"] = 1;
$response["message"] = "successfully signed Up.";

// echoing JSON response
echo json_encode($response);}
else {
// failed to insert row
$response["success"] = 0;
$response["message"] = "Oops! An error occurred.";

// echoing JSON response
echo json_encode($response);
}
} else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";

// echoing JSON response
echo json_encode($response);

}
?>

最佳答案

解析数据时出错 org.json.JSONException

这个错误是因为服务器端的响应不是预期的,所以paring json响应失败。

在你的 PHP 脚本中我看到了一个问题

// check for successful store
if ($result) {
// get user details
$uid = mysql_insert_id(); // last inserted id
$result = mysql_query("SELECT * FROM users WHERE uid = $uid");
// return user details
return mysql_fetch_array($result);
} else {
return false;
}

在此 block 中,if 和 else 中都有 return 语句,因此无法访问之后编写的代码。我不明白下面的代码是做什么的,但是如果插入了数据,则必须使用 json_encode 以 json 的形式进行响应。所以为此你必须从 if block 中删除 return

// check for successful store
if ($result) {
// get user details
$uid = mysql_insert_id(); // last inserted id
$result = mysql_query("SELECT * FROM users WHERE uid = $uid");
// return user details
echo json_encode(mysql_fetch_array($result));
exit;
}

使用 api 的一些建议 1. 首先通过 postman 从网上检查您的结果,并确认输出符合您的要求。 2.在android中使用debugging找出错误。

调试代码非常有用。

关于php - 使用 PHP 通过 Android 从 MySQL 插入和接收数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18417406/

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