c - 将指向 C 数组的指针传递给函数

Question

我对将指针传递给 char 数组有什么误解？

Request pointer in fun: 0x7fffde9aec80Response pointer in fun: 0x7fffde9aec80Response pointer: (nil), expected: 0x7fffde9aec80Response itself: (null), expected: Yadda

#include <stdlib.h>
#include <stdio.h>
#include <string.h>

int get_response(char *request, char **response) {
    response = &request;
    printf("Request pointer in fun: %p\n", request);
    printf("Response pointer in fun: %p\n", *response);
    return 0;
}

int main() {
    char *response = NULL, request[] = "Yadda";

    get_response(request, &response);

    printf("Response pointer: %p, expected: %p\n", response, request);
    printf("Response itself: %s, expected: %s\n", response, request);

    return 0;
}

Answer 1

在函数 get_response 中，您将 request 的地址存储在临时变量 response 中。你想把它存储在response指向的地方。

*response = request;