c - 3 个数字中的第二大，使用 if_else

Question

我是 C 编程的新手，最近遇到了从 3 个数中找出第二大数的问题。我尝试使用 if...else，但它总是给出最小的数字作为输出。我在这段代码中犯的逻辑错误是什么？

#include<stdio.h>

int main() {
    int a;
    int b;
    int c;
    a=10;
    b=30;
    c=7;
    if(a>b) {
        if(a>c) {
            if(b>c)
                printf("2nd largest is %d",c);
            else
                printf("2nd largest is %d",b);
        }
    } else

    {
        if(b>c) {
            if(c>a)
                printf("2nd largest is %d",a);
            else
                printf("2nd largest is %d",c);
        } else
            printf("2nd largest is %d",b);
    }
}

Answer 1

if(a>b) {
    if(a>c) { //a is the greatest!
        if(b>c) // the *greater* of the two remaining is the second greatest
            printf("2nd largest is %d",c); // if b > c, output b!
        else
            printf("2nd largest is %d",b); // if c > b, output c! 
    } // I think this got missed:  What if c > a and a > b?
} else

{
    if(b>c) { //b is the greatest!
        if(c>a) //As above, the *greater* of the two remaining is what you are looking for
            printf("2nd largest is %d",a); // c is greater, so output it
        else
            printf("2nd largest is %d",c); // a is greater
    } else // c > b and b > a, this is correct.
        printf("2nd largest is %d",b);
}