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C 连接整数

转载 作者:太空狗 更新时间:2023-10-29 15:01:26 25 4
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我会第一个承认,我是 100% 的 C# 人,C 不适合我。但是我有问题。我需要将 7 与 HashUrl(HashInt) 连接起来,然后再与 HashInt 连接起来任何帮助将不胜感激。

int main(int argc)
{
unsigned int HashInt;
HashInt = HashURL(argc);
// I need to return 7 + CheckHash(HashInt) + HashInt but not ADDING, but concanenating them
return HOWEVERTOGETTHESTRING;
}

我应该指定它的用法。它实际上将用于学生的 VB6 项目。

Private Declare Function main Lib "checksum.dll" (ByVal pStr As String) As Long

Private Sub Command1_Click()
MsgBox main("http://hello.com")
End Sub

C 库的完整源代码是

#include <stdio.h>
#include <string.h>
#include <windows.h>
#include <string.h>
#include <winreg.h>
#include <stdlib.h>

int StrToInt(char *pStr, int Init, int Factor)
{
while (*pStr) {
Init *= Factor;
Init += *pStr++;
}
return Init;
}

int HashURL(char *pStr)
{
unsigned int C1, C2, T1, T2;

C1 = StrToInt(pStr, 0x1505, 0x21);
C2 = StrToInt(pStr, 0, 0x1003F);
C1 >>= 2;
C1 = ((C1 >> 4) & 0x3FFFFC0) | (C1 & 0x3F);
C1 = ((C1 >> 4) & 0x3FFC00) | (C1 & 0x3FF);
C1 = ((C1 >> 4) & 0x3C000) | (C1 & 0x3FFF);

T1 = (C1 & 0x3C0) << 4;
T1 |= C1 & 0x3C;
T1 = (T1 << 2) | (C2 & 0xF0F);

T2 = (C1 & 0xFFFFC000) << 4;
T2 |= C1 & 0x3C00;
T2 = (T2 << 0xA) | (C2 & 0xF0F0000);

return (T1 | T2);
}

char CheckHash(unsigned int HashInt)
{
int Check = 0, Flag = 0;
int Remainder;

do {
Remainder = HashInt % 10;
HashInt /= 10;
if (1 == (Flag % 2) ){
Remainder += Remainder;
Remainder = (Remainder / 10) + (Remainder % 10);
}
Check += Remainder;
Flag ++;
} while( 0 != HashInt);

Check %= 10;
if (0 != Check) {
Check = 10 - Check;
if (1 == (Flag % 2)) {
if (1 == (Check % 2)) {
Check += 9;
}
Check >>= 1;
}
}
Check += 0x30;
return Check;
}

int main(int argc)
{
unsigned int HashInt;
int result;
HashInt = HashURL(argc);
char temp[100];
sprintf(temp, "7%i%j", CheckHash(HashInt), HashInt);
result = atoi(temp);
return result;
}

给“http://www.hello.com”应该返回 783544359868 但它不是

最佳答案

您可以使用 sprintf 函数来创建格式化字符串。要将 3 个整数连接成一个字符串,您可以使用类似的东西

sprintf(string, "%d%d%d", int1, int2, int3)

关于C 连接整数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3902640/

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