c - 如何从字符串中删除所有出现的特定字符？

Question

您好，我正在尝试从 C 字符串中删除一个字符，但输出似乎不正确。如果例如。输入字符串 = "你好"要删除的指定字符 = "l"我的输出是“HeXXo”。我似乎需要在删除字符后将值插入？

代码如下:

#include <stdio.h>
#include <stdlib.h>

void squeeze(char str[], char c);

void main (){
  char input[100];
  char c;
  printf("Enter string \n");
  gets(input);
  printf("Enter char \n");
  scanf("%c", &c);
  printf("char is %c \n", c);
  squeeze(input , c );

  getchar();
  getchar();
  getchar();
}

void squeeze(char str[], char c){
    int count = 0, i = 0;   

    while (str[count] != '\0'){
      count++;
    }

    printf("Count = %d  \n", count);
    for ( i = 0 ; i != count; i++){
      if (str[i] == c){
            printf("Found at str[%d] \n", i);
            str[i] = "";
      }
    }
    printf(" String is = %s", str);
}

Answer 1

str[i] = "";

您正在尝试分配一个指针而不是一个字符。您的意思可能是 ' ' 但这也不是从字符串中删除字符的正确方法，而是替换它们。尝试:

char *p = str;
for (i = 0 ; i != count; i++) {
    if (str[i] != c)
        *p++ = str[i];
}
*p = 0;

---

编辑

这里有一个我比较喜欢的解决方案:

char *p = s; /* p points to the most current "accepted" char. */
while (*s) {
    /* If we accept a char we store it and we advance p. */
    if (*s != ch)
        *p++ = *s;

    /* We always advance s. */
    s++;
}
/* We 0-terminate p. */
*p = 0;