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android - 在 gradle 中,我应该排除分支下的所有依赖项还是仅根目录就足够了?

转载 作者:太空狗 更新时间:2023-10-29 14:53:33 27 4
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我已将以下自定义任务添加到我的 build.gradle 文件中,以便打印出依赖项的依赖项。

// This part is useful for finding conflict resolution(s) between dependencies in order to exclude them.
// You can change the custom value and run following command in terminal:
// ./gradlew passenger-sdk:dependencies --configuration custom
configurations {
custom
}

dependencies {
custom 'com.google.android.gms:play-services-analytics:7.3.0'
}

所以结果是:

$ ./gradlew passenger-sdk:dependencies --configuration custom
:passenger-sdk:dependencies

------------------------------------------------------------
Project :passenger-sdk
------------------------------------------------------------

custom
\--- com.google.android.gms:play-services-analytics:7.3.0
\--- com.google.android.gms:play-services-base:7.3.0
\--- com.android.support:support-v4:22.0.0
\--- com.android.support:support-annotations:22.0.0

BUILD SUCCESSFUL

Total time: 1.681 secs

我想排除它的所有依赖项,因为我有它们。我应该排除所有三个依赖项 play-services-basesupport-v4support-annotations 还是只排除 play-services-base 够了吗?

最佳答案

排除 play-services-base 应该就足够了。由于您已经排除了父依赖项,因此如果没有更多依赖项,将不会提供 support-v4support-annotations

如果有更多的依赖,同样的配置需要support-v4support-annotations,那么你必须额外排除它们,但是它可以为整个配置完成一次。

关于android - 在 gradle 中,我应该排除分支下的所有依赖项还是仅根目录就足够了?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33333896/

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