c - C中的sprintf，循环永远不会结束

Question

我遇到循环问题，我不知道为什么但循环永远不会结束。

int main(int argc, char *argv[])
{
    int j;
    char s[2];
    for(j=1;j<=3;j++)
    {
        sprintf(s,"s%d",j);
        printf("%s", s);
    }
    system("PAUSE");    
    return 0;
}

我认为循环应该在控制台中显示 s1s2s3。

Answer 1

char s[2]; 应该是 char s[3];，否则你会得到缓冲区溢出。

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Abhineet解释为什么需要进行更改。但是，为了证实他的回答，这里是标准中的相关部分。

7.19.6.6

The sprintf function is equivalent to fprintf, except that the output is written into an array (specified by the argument s) rather than to a stream. A null character is written at the end of the characters written; it is not counted as part of the returned value. If copying takes place between objects that overlap, the behavior is undefined.