python BeautifulSoup 获取 select.value 而不是文本

Question

<select>
  <option value="0">2002/12</option>
  <option value="1">2003/12</option>
  <option value="2">2004/12</option>
  <option value="3">2005/12</option>
  <option value="4">2006/12</option>
  <option value="5" selected>2007/12</option>
</select>

使用此代码，我需要值作为 '0' 而不是文本作为 '2002/12'

我尝试了很多BS4选项，.stripped_strings, .strip(), .contents, get()等

如何获取值而不是文本？

Answer 1

您需要值 属性；访问tag attributes使用映射语法:

option['value']

演示:

>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('''\
... <select>
...   <option value="0">2002/12</option>
...   <option value="1">2003/12</option>
...   <option value="2">2004/12</option>
...   <option value="3">2005/12</option>
...   <option value="4">2006/12</option>
...   <option value="5" selected>2007/12</option>
... </select>
... ''')
>>> for option in soup.find_all('option'):
...     print 'value: {}, text: {}'.format(option['value'], option.text)
... 
value: 0, text: 2002/12
value: 1, text: 2003/12
value: 2, text: 2004/12
value: 3, text: 2005/12
value: 4, text: 2006/12
value: 5, text: 2007/12