android - 如何在键盘下绘制其他应用程序？

Question

我正在开发一个在屏幕上绘制气泡的 float 应用程序。我想让气泡在出现时始终位于键盘下方，或者至少捕获键盘事件。

这是我用来将气泡添加到窗口管理器的参数代码:

         params = new WindowManager.LayoutParams(
                WindowManager.LayoutParams.WRAP_CONTENT,
                WindowManager.LayoutParams.WRAP_CONTENT,
                WindowManager.LayoutParams.TYPE_PHONE,
                WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE 
                | WindowManager.LayoutParams.FLAG_LAYOUT_NO_LIMITS
                | WindowManager.LayoutParams.FLAG_TRANSLUCENT_NAVIGATION
                | WindowManager.LayoutParams.FLAG_TRANSLUCENT_STATUS
                | WindowManager.LayoutParams.FLAG_DRAWS_SYSTEM_BAR_BACKGROUNDS,
                PixelFormat.TRANSLUCENT);

我已经尝试了所有窗口类型/标志，但无法实现。我知道这是可能的，因为“EAS: easy app switcher”做到了。

我真的希望有人能在这方面启发我。提前感谢您的宝贵时间!

Answer 1

我刚刚遇到了同样的问题，终于找到了解决方案。虽然它可能不会再帮助您，但希望它能帮助遇到同样问题的其他人。

需要的标志是 WindowManager.LayoutParams.FLAG_ALT_FOCUSABLE_IM 与 WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE 的组合。

这是 javadoc 中关于标志的内容:

    /** Window flag: invert the state of {@link #FLAG_NOT_FOCUSABLE} with
     * respect to how this window interacts with the current method.  That
     * is, if FLAG_NOT_FOCUSABLE is set and this flag is set, then the
     * window will behave as if it needs to interact with the input method
     * and thus be placed behind/away from it; if FLAG_NOT_FOCUSABLE is
     * not set and this flag is set, then the window will behave as if it
     * doesn't need to interact with the input method and can be placed
     * to use more space and cover the input method.
     */