android - android getView() 如何在 BaseAdapter 中工作？

Question

我读过一些文章并看过video为了理解 ListView 是如何工作的。因此，假设我有包含 5 个项目的列表(所有项目都在屏幕上可见)。我的自定义适配器中有以下代码，它继承自 BaseAdapter:

@Override
public View getView(int position, View view, ViewGroup parent) {
    System.out.println("item position: " + position + " view " + view);

    if (view == null)
    {
        view = LayoutInflater.from(context).inflate(R.layout.list_view_item, null);
    }
    return view;
}

当我运行这段代码时，我在控制台中看到以下输出:

08-26 14:52:40.882: item position: 0 view null
08-26 14:52:40.883: item position: 1 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.883: item position: 2 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 3 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 4 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 0 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 1 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 2 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 3 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 4 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 0 view android.widget.RelativeLayout{88bc756 V.E...C.. ......I. 0,0-1080,65 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 1 view android.widget.RelativeLayout{1264e60 V.E...C.. ......I. 0,68-1080,133 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 2 view android.widget.RelativeLayout{36b089 V.E...C.. ......I. 0,136-1080,201 #7f0e00b8 app:id/item_container}
08-26 14:52:40.884: item position: 3 view android.widget.RelativeLayout{e1a12bb V.E...C.. ......I. 0,204-1080,269 #7f0e00b8 app:id/item_container}
08-26 14:52:40.885: item position: 4 view android.widget.RelativeLayout{ab5ffdd V.E...C.. ......I. 0,0-0,0 #7f0e00b8 app:id/item_container}

I getView() view 为 null 仅对于 0 位置。观看之后，我认为前 5 次调用的 null(直到所有可见项目 View 未初始化)。为什么只针对第一个？我缺少什么？

Answer 1

ListView 回收 View ，因此第一次运行它将是 null 因为您必须膨胀 View 。膨胀 View 后，您应该重用相同的 View 并仅更新内容以提高性能。我建议观看以下视频 https://www.youtube.com/watch?v=wDBM6wVEO70 ，他们很好地解释了 ListView 的工作原理。