gpt4 book ai didi

android - 多列列表中的 nullPointerException

转载 作者:太空狗 更新时间:2023-10-29 13:38:29 24 4
gpt4 key购买 nike

我已经在 SO 上尝试过类似问题的引用,但没有找到合适的解决方案。

我正在尝试从网页中获取数据并以包含 4 列的行的格式显示它。

网页上的数据:

SBIN ;1916.00;1886.85;1.54@LT ;1315.50;1310.30;0.40@TCS ;1180.00;1178.00;0.17@AXISBANK ;1031.30;1005.95;2.52@MARUTI ;1000.35;PN.35;998.0;392.19 916.35;1.70@盖尔;400.00;398.45;0.39@

我想在表单中显示它

SBIN.........1916.00.....1886.85.....1.54

LT...........1315.50.....1310.30.....0.40 and so on.

请注意,我不想要点,我希望每个值都是一行中的一个单独的列。

我的数据由 7 行组成。

当我运行下面的代码时,我得到这个输出 Screenshot

 values[0]   values[1]   values[2]   values[3]

values[1] values[2] values[3] values[4]

values[2] values[3] values[4] values[5]

(它打印第一行的所有 4 列,然后是第一行的 2-4 列和第二行的 col1,然后是第一行的 3-4 列和第二行的 1-2 列,依此类推...)

ReadWebpageAsyncTask.java

public class ReadWebpageAsyncTask extends Activity {
private EditText ed;
private ListView lv;

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
ed = (EditText) findViewById(R.id.ed);
lv = (ListView) findViewById(R.id.list);
DownloadWebPageTask task = new DownloadWebPageTask();
task.execute(new String[] { "http://abc.com/default.aspx?id=G" });
}

private class DownloadWebPageTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {
String response = "";
for (String url : urls) {
DefaultHttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
try {
HttpResponse execute = client.execute(httpGet);
InputStream content = execute.getEntity().getContent();

BufferedReader buffer = new BufferedReader(
new InputStreamReader(content));
String s = "";
while ((s = buffer.readLine()) != null) {
response += s;
}

} catch (Exception e) {
e.printStackTrace();
}
}
return response;
}

@Override
protected void onPostExecute(String result) {
int sub = result.lastIndexOf('@', result.length() - 1);
String s1 = result.substring(0, sub + 2);
String temp[];
String subarr[] = new String[100];
;
Log.v("data = ", s1);
// String s = s1.replace(";", " - ");
final String arr[] = s1.split("@");

for (int i = 0; i < arr.length; i++) {
Log.v("arr" + i, arr[i] + " " + arr.length);
}

for (int i = 0; i < arr.length - 1; i++)

{
temp = arr[i].split(";");
subarr[(4 * i)] = temp[0];
subarr[(4 * i) + 1] = temp[1];
subarr[(4 * i) + 2] = temp[2];
subarr[(4 * i) + 3] = temp[3];
}
lv.setAdapter(new MyAdapter(ReadWebpageAsyncTask.this, subarr));
}
}
}

ma​​in.xml

            <?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="match_parent">

<EditText android:id="@+id/ed"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="Search">
</EditText>

<ListView android:id="@+id/list"
android:layout_width="wrap_content"
android:layout_height="wrap_content">
</ListView>

</LinearLayout>

MyAdapter.java

   public class MyAdapter extends ArrayAdapter<String> {
private final Context context;
private final String[] values;

private String item1, item2, item3, item0;
int x = 0, i = 1, y = 1;

public MyAdapter(Context context, String[] values) {
super(context, R.layout.row, values);
this.context = context;
this.values = values;
}

@Override
public String getItem(int position) {
return values[position];
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {

LayoutInflater inflater = (LayoutInflater) context
.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View rowView = inflater.inflate(R.layout.row, parent, false);
TextView tv1 = (TextView) rowView.findViewById(R.id.col1);
TextView tv2 = (TextView) rowView.findViewById(R.id.col2);
TextView tv3 = (TextView) rowView.findViewById(R.id.col3);
TextView tv4 = (TextView) rowView.findViewById(R.id.col4);

if (y < 8) {
item0 = getItem(position);
Log.v("pos = ", "" + position);
item1 = getItem(position + 1);
item2 = getItem(position + 2);
item3 = getItem(position + 3);

tv1.setText(item0);
tv2.setText(item1);
tv3.setText(item2);
tv4.setText(item3);

} else {
Log.v("y= ", "" + y);
}
return rowView;
}
}

行.xml

    <?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="horizontal" >

<TextView android:id="@+id/col1"
android:layout_width="150dip"
android:layout_height="wrap_content"/>

<TextView android:id="@+id/col2"
android:layout_width="70dip"
android:layout_height="wrap_content"/>

<TextView android:id="@+id/col3"
android:layout_width="70dip"
android:layout_height="wrap_content"/>

<TextView android:id="@+id/col4"
android:layout_width="match_parent"
android:layout_height="wrap_content"/>

</LinearLayout>

任何适用的帮助

最佳答案

尝试使用 ListView

代替 TableLayout 将 ListView 添加到您的 xml 并将内容放在新 xml 中的表中通过扩展 ArrayAdapter 创建一个适配器,并在你的 listView 上设置这个适配器。

关于android - 多列列表中的 nullPointerException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8395750/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com