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android - 在 webview 中保持从 Android 应用程序到网站的 session 打开

转载 作者:太空狗 更新时间:2023-10-29 13:36:59 25 4
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我有一个正在创建的 Android 应用程序,我有一个登录页面作为第一个 Intent 。然后这将打开一个选项卡持有者并将用户带到第一个选项卡,这将显示一个 web View 。网站是应用程序的重要组成部分,需要用户登录。网站和应用程序使用在同一台服务器上运行的相同登录脚本,因此登录信息是相同的。我想使用在登录到 webview 内的应用程序时创建的 session ,以便当用户进入 webview 时他们仍然登录。我尝试使用共享首选项重新登录 webview 但事实并非如此在职的。我能够将共享首选项传递给它,但它仍然告诉我我没有登录该网站。对此主题的任何帮助将不胜感激。

这是我的代码:

用于创建我将在所有类之间传递的 defaultHttpRequest 的连接类。

import java.io.IOException;

import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;

public class Connection1 {


public static HttpClient httpclient = new DefaultHttpClient();
private static HttpPost httpPost;

public Connection1(){
}

public HttpPost getHttpPost(){
return httpPost;
}
public HttpResponse getResponse() throws ClientProtocolException, IOException{
return httpclient.execute(httpPost);
}
public void setEntity(UrlEncodedFormEntity entity){
httpPost.setEntity(entity);
}
public void setHttpPost(String script){
httpPost = new HttpPost(script);
}
}

将显示网站页面的 Webapp 类:

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;

import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.message.BasicNameValuePair;

import android.app.Activity;
import android.content.SharedPreferences;
import android.os.Bundle;
import android.webkit.WebView;
import android.webkit.WebViewClient;

public class WebApp extends Activity {

public static final String PREFS_NAME = "myPrefsFile";
private static final String PREFS_USERNAME = "username";
private static final String PREFS_PASSWORD = "password";

String username = "";
String password = "";

@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
}

@Override
protected void onResume() {
// TODO Auto-generated method stub
super.onResume();
setContentView(R.layout.webapp);
SharedPreferences pref = getSharedPreferences(PREFS_NAME, MODE_PRIVATE);
username = pref.getString(PREFS_USERNAME, null);
password = pref.getString(PREFS_PASSWORD, null);
System.out.println(username + "-" + password);
postLoginData();


}

public void postLoginData() {

// Create a new HttpClient and Post Header
Connection1 connection = new Connection1();
connection
.setHttpPost("script.php");

try {

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("username", username));
nameValuePairs.add(new BasicNameValuePair("password", password));
connection.setEntity(new UrlEncodedFormEntity(nameValuePairs));

String str = inputStreamToString(
connection.getResponse().getEntity().getContent())
.toString();

if (str.toString().equalsIgnoreCase("success")) {
WebView webapp = (WebView) findViewById(R.id.webView1);
webapp.loadUrl("URL");
webapp.setWebViewClient(new WebViewClient());
webapp.getSettings().setJavaScriptEnabled(true);
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}

private StringBuilder inputStreamToString(InputStream is) {
String line = "";
StringBuilder total = new StringBuilder();
// Wrap a BufferedReader around the InputStream
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
// Read response until the end
try {
while ((line = rd.readLine()) != null) {
total.append(line);
}
} catch (IOException e) {
e.printStackTrace();
}
// Return full string
return total;
}
}

最佳答案

在您的 WebView 实例上,调用它。

webView.setHttpAuthUsernamePassword(url,"", "@"+username, password);

并覆盖下面的方法:

@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url+"?name="+username+"&password="+password);
view.loadUrl(url);
return true;
}

关于android - 在 webview 中保持从 Android 应用程序到网站的 session 打开,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9543352/

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