android - 使用 SpringFramework Android Rest Client 出现 422 错误时获取 Web 服务消息

Question

我正在开发一个连接到 Web 服务的 Android 应用程序。从网络服务我得到这个错误:

POST request for "xxx" resulted in 422 (Unprocessable Entity); invoking error handler

我正在使用适用于 Android 的 SpringFramework Rest Client，并使用以下代码连接到 Web 服务:

public static User sendUserPersonalData(User userProfileData)
{
    try
    {
        HttpHeaders requestHeaders = new HttpHeaders();
        requestHeaders.setAccept(Collections.singletonList(new MediaType("application","json")));
        HttpEntity<User> requestEntity = new HttpEntity<User>(userProfileData, requestHeaders);

        GsonHttpMessageConverter messageConverter = new GsonHttpMessageConverter();
        List<HttpMessageConverter<?>> messageConverters = new ArrayList<HttpMessageConverter<?>>();
        messageConverters.add(messageConverter);

        HttpComponentsClientHttpRequestFactory requestFactory = new HttpComponentsClientHttpRequestFactory();
        requestFactory.setReadTimeout(readTimeout);

        RestTemplate restTemplate = new RestTemplate(requestFactory);
        restTemplate.setMessageConverters(messageConverters);

        String url = URL_BASE_WEB + USER_PERSONAL_DATA_CALL;
        ResponseEntity<User> responseEntity = restTemplate.exchange(url, HttpMethod.POST, requestEntity, User.class);

        return responseEntity.getBody();
    }
    catch (Exception e)
    {
        e.printStackTrace();
    }
    return null;
}

但是，网络服务也会返回一个像这样的 JSON 字符串:

{
    "email": [
        "is invalid"
    ],
    "birthday": [
        "is invalid"
    ],
    "startday": [
        "is invalid"
    ],
    "sex_preference": [
        "can't be blank"
    ],
    "password": [
        "is too long (maximum is 4 characters)"
    ]
}

即使得到了Exception，如何获取？

Answer 1

你应该 catch RestClientException像这样:

  try{
     ....
     restTemplate.exchange(...);
  }catch(RestClientException e){
     //process exception
     if(e instanceof HttpStatusCodeException){
         String errorResponse=((HttpStatusCodeException)e).getResponseBodyAsString();
         //now you have the response, construct json from it, and extract the errors
     }

  }

查看 RestTemplate 的 javadocs , RestClientException .