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Android Asynctasks,在 Activity 之间传递字符串

转载 作者:太空狗 更新时间:2023-10-29 13:28:53 25 4
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我正在尝试将微调器设置的字符串 (locationSet) 从一个 Activity 传递到另一个 Activity ,它们都在每个类中实现一个 Asynchtask。

我无法将值从 MainActivity 传递到我的 WeatherActivity。使用日志,我可以看到在 MainActivity 中设置的初始值很好,但每次我尝试将其传递给天气 Activity 时都为空。如果我在 WeatherActivity 中手动输入相关字符串,输出将按预期工作。

我已经查看了其他问题,但我发现很难应用我看到的任何东西。

MainActivity.java

public class MainActivity extends Activity {

Button searchLocation;
Spinner locationSpinner;
String locationSet = null;
String strLocation = null;
Locations arrLocation;




@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
searchLocation = (Button) findViewById(R.id.searchLocationButton);

locationSpinner = (Spinner) findViewById(R.id.locationsListView);

ArrayAdapter<CharSequence> adaptor = ArrayAdapter.createFromResource(this, R.array.location_array, android.R.layout.simple_list_item_1);
locationSpinner.setAdapter(adaptor);

searchLocation.setOnClickListener(new View.OnClickListener() {

@Override
public void onClick(View v) {

new MyAsync().execute();

}
});
}

public void onBackPressed() {
super.onBackPressed();
this.finish();
}

class MyAsync extends AsyncTask<Void, Void, Void> {

@Override
protected Void doInBackground(Void... params) {
return null;
}

@Override
protected void onPostExecute(Void result) {

strLocation = locationSpinner.getSelectedItem().toString();

if (strLocation.equals("Aberdeen")) {
locationSet = arrLocation.ABERDEEN;
} else if (strLocation.equals("Dundee")) {
locationSet = arrLocation.DUNDEE;
} else if (strLocation.equals("Edinburgh")) {
locationSet = arrLocation.EDINBURGH;
} else if (strLocation.equals("Fort William")) {
locationSet = arrLocation.FORT_WILLIAM;
} else if (strLocation.equals("Glasgow")) {
locationSet = arrLocation.GLASGOW;
} else if (strLocation.equals("Manchester")) {
locationSet = arrLocation.MANCHESTER;
} else if (strLocation.equals("North Berwick")) {
locationSet = arrLocation.NORTH_BERWICK;
} else if (strLocation.equals("Portree")) {
locationSet = arrLocation.PORTREE;
} else if (strLocation.equals("Ullapool")) {
locationSet = arrLocation.ULLAPOOL;
}

Intent intent = new Intent(MainActivity.this, WeatherActivity.class);
startActivity(intent);
}
}

WeatherActivity.java

    public class WeatherActivity extends MainActivity {

TextView firstDayTextView;

String selectedLocation = null;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.weather_activity);

locationTextView = (TextView) findViewById(R.id.locationTextView);



new LoginAsync().execute();
}

class LoginAsync extends AsyncTask<Void, Void, Void> {
MySaxHandler myHandler;

StringBuilder builder = new StringBuilder();

@Override
protected Void doInBackground(Void... params) {
myHandler = new MySaxHandler();
myHandler.addLocation(selectedLocation.toString());
myHandler.get();
return null;
}

@Override
protected void onPostExecute(Void result) {

ArrayList<ItemData> items = myHandler.items;

if (null != items && items.size() != 0) {
for (int index = 0; index < items.size(); index++) {
ItemData obJPost = items.get(index);
builder.append("\n" + obJPost.getItemTitle());
}
}
firstDayTextView.setText(builder.toString());

}
}
}

最佳答案

您可以在开始天气 Activity 时使用 Intent.putExtra("TAG", locationSet) 传递您的字符串值“locationSet”。在 onCreate 的天气 Activity 中,您可以使用 Intent.getExtra 获取值。

代码示例:

Intent i = new Intent(FirstScreen.this, SecondScreen.class);   
String keyIdentifer = null;
i.putExtra("STRING_I_NEED", strName);

Then, to retrieve the value try something like:
String newString;
if (savedInstanceState == null) {
extras = getIntent().getExtras();
if(extras == null) {
newString= null;
} else {
newString= extras.getString("STRING_I_NEED");
}
} else {
newString= (String) savedInstanceState.getSerializable("STRING_I_NEED");
}

关于Android Asynctasks,在 Activity 之间传递字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18306172/

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