java - android中所有 Activity 的单一socket.IO连接

Question

我已经为 SocketIOClient 引用创建了 Singleton 类 here .服务器已连接。我可以将请求从 Activity 发送到 SocketIOClient。但是我怎样才能从 Activity 中的 Singleton 类得到响应呢？

这是我的 Activity :

import java.net.MalformedURLException;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;


public class MainActivity extends Activity {
    EditText uname, passwd;
    Button login;
    JSONObject json;
    SocketIOClient socket;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    socket = new SocketIOClient();
    try {
        SocketIOClient.initInstance();
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    json = new JSONObject();
    uname = (EditText) findViewById(R.id.unameED);
    passwd = (EditText) findViewById(R.id.passwdED);
    login = (Button) findViewById(R.id.loginButton);
    login.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

            try {
                json.put("username", uname.getText().toString().trim());
                json.put("password", passwd.getText().toString().trim());
              //request send to server    
                SocketIOClient.emit("login_request", json);

            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }
    });

}

} 

我的单例类也有 on() 方法:

        @Override
        public void on(String event, IOAcknowledge ack, Object... args) {
            JSONArray jarr_args = new JSONArray();
            JSONObject jobj_in = new JSONObject();
            if (event.equals("registration_status")) {
                jarr_args.put(args[0]);
                try {
                    jobj_in = jarr_args.getJSONObject(0);
                    Log.d("Result", jobj_in.getString("result"));
                    if (jobj_in.getString("result").equals("success")) {

                    } else {
                        Log.d("check:", "username and password");

                    }
                } catch (JSONException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            }
        }

这里单例类可以得到服务器的响应。但我想知道，如何在我的 Activity 中获得响应？

Answer 1

像这样创建一个抽象类

public abstract class ResponseHandler 
{
    private Context context;

    public abstract void execute (JSONObject jsonObject) throws JSONException;

    public ResponseHandler (Context ctx)
    {
        this.context = ctx;
    }

    public void handleObject(JSONObject jsonObject) throws Exception
    {
        execute(jsonObject);

    }
}

在你的 Activity 中在调用套接字类时，也将 ResponseHadler 作为参数传递示例:

SocketIOClient.initInstance(your parameters, new ResponseHandler(this)
{
    //ResponseHandler have an abstract method called execute(). So you are overriding it here
    @Override
    public void execute(JSONObject jsonObject) throws JSONException
    {
        // Here you will get your JSONObject passed from socket class
    }
}

在你的套接字类中

public class YourSocketClass
{
private ResponseHandler handler;

public static void initInstance(your parameter, ResponseHandler responseHandler)
{
    this.handler = responseHandler;

    // Do your operations here      
}

@Override
public void on(String event, IOAcknowledge ack, Object... args) 
{
    JSONArray jarr_args = new JSONArray();
    JSONObject jobj_in = new JSONObject();
    if (event.equals("registration_status")) 
    {
        jarr_args.put(args[0]);
        try 
        {
            jobj_in = jarr_args.getJSONObject(0);
            Log.d("Result", jobj_in.getString("result"));
            if (jobj_in.getString("result").equals("success")) 
            {
                //If you want to pass your jsonobject from here to activity
                //Do something like this
                handler.handleObject(jobj_in);
            } 
            else 
            {
                Log.d("check:", "username and password");
            }
        } 
        catch (JSONException e) 
        {
            e.printStackTrace();
        }
    }
}
}