android - java.lang.IllegalStateException : Expected a string but was BEGIN_OBJECT at line 1 column 2 path $ 错误

Question

我创建了 Retrofit 界面

public interface UserService {
    @GET(Constants.Api.URL_LOGIN)
    Call<String> loginUser(@Query("email") String email, @Query("password") String pass, @Query("secret") String secret, @Query("device_id") String deviceid, @Query("pub_key") String pubkey, @Query("device_name") String devicename);

在 Activity 中调用

final Call<String> responce = service.loginUser(loginedt.getText().toString(), md5(passwordedt.getText().toString()), secret, device_id, pub_key, device_name);

                    responce.enqueue(new Callback<String>() {
                        @Override
                        public void onResponse(Response<String> response) {
                            if (response.code() == Constants.Status.ERROR_404) {
                                Toast.makeText(LoginActivity.this, getResources().getString(R.string.wrong_log_pass), Toast.LENGTH_LONG).show();
                            } else if (response.code() != Constants.Status.ERROR_404 && response.code() != Constants.Status.SUCCES) {
                                Toast.makeText(LoginActivity.this, getResources().getString(R.string.wrong_request), Toast.LENGTH_LONG).show();
                            } else {
                                startActivity(new Intent(LoginActivity.this, MainActivity.class));
                            }
                        }

                        @Override
                        public void onFailure(Throwable t) {
                            t.printStackTrace();

                        }
                    });

我遇到了错误

onFailure java.lang.IllegalStateException: Expected a string but was BEGIN_OBJECT at line 1 column 2 path $

Answer 1

如果您不创建自己的模型，请使用 Call<JsonObject> .

这是 application/json 内容类型请求的默认解析器。