android - 启动服务后立即调用 finish() 的正确方法

Question

我喜欢在启动服务后立即退出我的应用程序。

下面的代码使 Activity 在服务启动之前完成。如何设置监听器在服务启动时提示我？

btn  = (ImageButton) findViewById(R.id.button );
        btn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                startService(new Intent(MainActivity.this, MyService.class));

                //I want to exit the activity here.
                finish(); // this exits the activity before the service is started

            }
        });

Answer 1

以下是我使用的代码，基于@Er.Arjunsaini 的提议

在 ACTIVITY 文件中，我注册收听“Exit App”广播。

private final BroadcastReceiver exitAppReceiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {
        //activity exits when "exit app" broadcast received.
        finish();
    }
};


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    //REGISTER TO LISTEN FOR THE BROADCAST
    LocalBroadcastManager.getInstance(this).
            registerReceiver(exitAppReceiver, new IntentFilter(getString(R.string.exit_app)));

    btn = (ImageButton) findViewById(R.id.my_button);
    btn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) { 
            startService( new Intent(this, MyService.class));

        }
    }); 
}

@Override
public void onDestroy() {

    //UNREGISTER THE RECEIVER
    LocalBroadcastManager.getInstance(this).
            unregisterReceiver(exitFloatingWindowReceiver);
    super.onDestroy();
}

在 SERVICE 文件上，我发送一个“退出 APP”广播。

@Override
public void onCreate() {
    super.onCreate();

    //... do the rest of the Service initializing 

    //CLOSE ACTIVITY
    LocalBroadcastManager.getInstance(this).
            sendBroadcast(new Intent(getString(R.string.exit_app)));
}