linux - 通过 Jenkins : "find: missing argument to ` -exec'"执行 Groovy 命令

Question

我正在尝试使用 Jenkins 管道脚本 (groovy) 将生成的 war 文件从一个构建目录复制到另一个构建目录。我已经作为 jenkins 用户在系统本身上测试了 find/exec/cp 命令，在脚本运行的同一工作区中，它工作正常(直接从控制台复制粘贴)。

String buildNumber = env.BUILD_NUMBER

def sout = new StringBuffer()
def serr = new StringBuffer()

//Create package directory in jenkins job folder
def packageDir = "${env.JENKINS_HOME}/jobs/Package_Deploy_Pipeline/builds/${buildNumber}/package/"
def command = "mkdir ${packageDir}"
def proc = command.execute()
proc.consumeProcessOutput(sout, serr)
proc.waitForOrKill(3000)
println "out> $sout err> $serr"

command = "find ${env.JENKINS_HOME}/jobs/myJob/builds/lastSuccessfulBuild/archive/build/libs/ -name *.war -exec cp {} ${packageDir} \\;"
println command
proc = command.execute()
proc.consumeProcessOutput(sout, serr)
proc.waitForOrKill(3000)
println "out> $sout err> $serr"

在控制台输出中看到的错误是:

[Pipeline] echo
out>  err> 
[Pipeline] echo
find /var/lib/jenkins/jobs/myJob/builds/lastSuccessfulBuild/archive/build/libs/ -name *.war -exec cp {} /var/lib/jenkins/jobs/Package_Deploy_Pipeline/builds/23/package/ \;
[Pipeline] echo
out>  err> find: missing argument to `-exec'

编辑:我也尝试过 "*.war"、'*.war'、\; 和 '; '

Answer 1

带有声明式管道的 Jenkins 只对我有效:

sh '找到 . -ipath "*src/header.h"-exec rm {} ";"'