python subprocess.call 参数问题

Question

我正在 Linux 下编写一个简单的 python 脚本，使用 subprocess 对我子网上的主机执行一批并发的单个 ping。

手动执行命令:ping -c 1 192.168.68.1

脚本::

#!/usr/bin/python
from subprocess import call

path = "ping"
flags = "-c 1 "

for i in range(1,3):
    ip_addr = "192.168.68." + str(i)
    args = flags + ip_addr

    print "doing: {} {}".format(path, args)        
    call([path, args])

注释掉调用输出预期的:

doing: ping -c 1 192.168.68.1
doing: ping -c 1 192.168.68.2

使用 call()，脚本似乎调用了 ping 但参数未知。输出如下:

doing: ping -c 1 192.168.68.1
Usage: ping [-aAbBdDfhLnOqrRUvV64] [-c count] [-i interval] [-I interface]
        [-m mark] [-M pmtudisc_option] [-l preload] [-p pattern] [-Q tos]
        [-s packetsize] [-S sndbuf] [-t ttl] [-T timestamp_option]
        [-w deadline] [-W timeout] [hop1 ...] destination
Usage: ping -6 [-aAbBdDfhLnOqrRUvV] [-c count] [-i interval] [-I interface]
         [-l preload] [-m mark] [-M pmtudisc_option]
         [-N nodeinfo_option] [-p pattern] [-Q tclass] [-s packetsize]
         [-S sndbuf] [-t ttl] [-T timestamp_option] [-w deadline]
         [-W timeout] destination
doing: ping -c 1 192.168.68.2
Usage: ping [-aAbBdDfhLnOqrRUvV64] [-c count] [-i interval] [-I interface]
        [-m mark] [-M pmtudisc_option] [-l preload] [-p pattern] [-Q tos]
        [-s packetsize] [-S sndbuf] [-t ttl] [-T timestamp_option]
        [-w deadline] [-W timeout] [hop1 ...] destination
Usage: ping -6 [-aAbBdDfhLnOqrRUvV] [-c count] [-i interval] [-I interface]
         [-l preload] [-m mark] [-M pmtudisc_option]
         [-N nodeinfo_option] [-p pattern] [-Q tclass] [-s packetsize]
         [-S sndbuf] [-t ttl] [-T timestamp_option] [-w deadline]
         [-W timeout] destination

似乎 ping 每次迭代都被调用了两次，args 与我预期的不同。我注意到 ping 提示的 -6 参数。
我将不胜感激任何帮助，尤其是在正确使用 call() 方面。

更新:
添加了我试图模拟的 bash 脚本:

#!/bin/bash
for ip in $(seq 1 2); do
    ping -c 1 192.168.68.$ip &
done

Answer 1

传递给函数 call 的参数都应该是列表中的单个元素，如下所示:

call(['ping','-c','1','192.168.68.2'])

我无法在我的环境中重现“双重打印”。