Linux : sed -e expression error

Question

我正在尝试使用 sed 递归替换 mysql 字符串，就像这样

find /var/www/html -type f -exec \
sed -i 'mysql_real_escape_string(/$conn->qStr(/g' {} +

目标

find: mysql_real_escape_string(
replace to: $conn->qStr(

但它给我错误:

sed: -e expression #1, char 1: unknown command: `m'
sed: -e expression #1, char 1: unknown command: `m'
sed: -e expression #1, char 1: unknown command: `m'

任何帮助都会很棒。谢谢

Answer 1

您应该提供 s 命令:

find /var/www/html -type f -exec \
sed -i 's/mysql_real_escape_string(/$conn->qStr(/g' {} +