c++ - pthread_mutex_lock 错误

Question

#include "MutexCondition.h"

bool MutexCondition::init(){
    printf("MutexCondition::init called\n");
    pthread_mutex_init(&m_mut, NULL);
    pthread_cond_init(&m_con, NULL);
    return true;
}

bool MutexCondition::destroy(){
    pthread_mutex_destroy(&m_mut);
    pthread_cond_destroy(&m_con);
    return true;
}

bool MutexCondition::lock(){
    pthread_mutex_lock(&m_mut);
    return true;
}

bool MutexCondition::unLock(){
    pthread_mutex_unlock(&m_mut);
    return true;
}

bool MutexCondition::wait(){
    pthread_cond_wait(&m_con, &m_mut);
    return true;
}

bool MutexCondition::signal(){
    pthread_cond_signal(&m_con);
    return true;
}

我正在从事网络编程，我有这个和扩展 MutexCondition 的 Sound 类

#ifndef SOUND_H_
#define SOUND_H_

#include <list>
#include "SoundMetaData.h"
#include "SoundSignature.h"
#include "../MutexCondition.h"

using namespace std;

class Sound : public MutexCondition{

private:
    SoundMetaData *m_metaData;
    list<SoundSignature*> m_soundSignatureList;

public:
    Sound(SoundMetaData *metaData);
    virtual ~Sound();
    SoundMetaData* getSoundMetaData();
    list<SoundSignature*> getSoundSignatureList();

    bool addApplication(string &application);
    bool removeApplication(string &application);
    void addSoundSignature(SoundSignature* signature);

};

#endif /* SOUND_H_ */

如果我在 gdb 上运行我的服务器。它在函数 getSoundSignatureList 的 pthread_mutex_lock () 上爆炸。

list<SoundSignature *> Sound::getSoundSignatureList(){
    lock();
    list<SoundSignature*> list(m_soundSignatureList);
    unLock();
    return list;
}

我有一个名为 Engine 的类，5 个不同的线程根据接收到的数据包类型创建 Engine 类。 Engine 类中的函数调用 getSoundSignatureList 类。还有任何其他地方可以调用 Engine 类。

我不明白它怎么会在 pthred_mutex_lock 上爆炸

我该如何解决这个问题？感谢您的帮助

编辑 .h 文件

#ifndef MUTEXCONDITION_H_
#define MUTEXCONDITION_H_

#include <pthread.h>
#include <stdio.h>

class MutexCondition {

private:
    bool init();
    bool destroy();

protected:

    pthread_mutex_t m_mut;
    pthread_cond_t m_con;

public:
    MutexCondition(){
        init();
    }
    virtual ~MutexCondition(){
        destroy();
    }

    bool lock();
    bool unLock();
    bool wait();
    bool signal();

};
#endif /* MUTEXCONDITION_H_ */

Answer 1

我想知道您的互斥锁实例是否由于复制或赋值操作而被丢弃(您甚至可能没有意识到)。互斥锁是不可复制的——您应该通过将复制构造函数和 operator=() 设为私有(private)和未实现(或类似技术)来确保您拥有的包装类不能被复制:

#ifndef MUTEXCONDITION_H_
#define MUTEXCONDITION_H_

#include <pthread.h>
#include <stdio.h>

class MutexCondition {

private:
    bool init();
    bool destroy();

    // idiom to prevent copying: don't implement these
    MutexCondition( MutexCondition const&);
    void operator=( MutexCondition const&);

protected:

    pthread_mutex_t m_mut;
    pthread_cond_t m_con;

public:
    MutexCondition(){
        init();
    }
    virtual ~MutexCondition(){
        destroy();
    }

    bool lock();
    bool unLock();
    bool wait();
    bool signal();

};
#endif /* MUTEXCONDITION_H_ */

另请注意:在我看来，此类的私有(private)继承可能比公共(public)继承更合适。