linux - bash array using @ vs *，两者的区别

Question

我无法确定使用 ${array[@]} 与 ${array[*]} 之间的确切区别

我看到的是打印时的差异，但我想还有更多差异

declare -a array
array=("1" "2" "3")
IFS=","
printf "%s" ${array[@]}
printf "%s" ${array[*]}
IFS=" "

我在 TLDP 上搜索了它，但无法弄清楚。它是一般的 bash 东西还是只用于数组？非常感谢!

Answer 1

如 man bash 中所述:

If the word is double-quoted, ${name[*]} expands to a single word with the value of each array member separated by the first character of the IFS special variable, and ${name[@]}expands each element of name to a separate word.

例子:

array=("1" "2" "3")
printf "'%s'" "${array[*]}"
'1 2 3'
printf "'%s'" "${array[@]}"
'1''2''3'