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c - inet_ntop : No space left on device

转载 作者:太空狗 更新时间:2023-10-29 11:24:29 30 4
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您好,我创建了一个函数,该函数将接受的 sockFD 作为输入,并将表示形式的 ip 地址输出为字符串。该函数似乎工作正常,直到我开始使用 inet_ntop 的调用来打包字符串,该调用返回一个空指针,从而给了我错误。错误显示为 No space left on device 我不明白,因为我有足够的 ram 和 rom。不管怎样,下面是我正在使用的功能。

void getTheirIp(int s, char *ipstr){ // int s is the incoming socketFD, ipstr points the the calling
// functions pointer.
socklen_t len;
struct sockaddr_storage addr;
len = sizeof(addr); //I want to store my address in addr which is sockaddr_storage type
int stat;
stat = getpeername(s, (struct sockaddr*)&addr, &len); // This stores addrinfo in addr
printf("getTheirIP:the value of getpeername %d\n",stat);
// deal with both IPv4 and IPv6:
if ((stat=addr.ss_family) == AF_INET) { // I get the size of the sock first
printf("getTheirIP:the value of addr.ss_family is %d\n",stat);
ipstr = malloc(INET_ADDRSTRLEN); // I allocate memory to store the string
struct sockaddr_in *s = (struct sockaddr_in *)&addr; // I then create the struct sockaddr_in which
// is large enough to hold my address
if(NULL == inet_ntop(AF_INET, &s->sin_addr, ipstr, sizeof(ipstr))){ // I then use inet_ntop to
printf("getTheirIP:the value of inet_ntop is null\n");// retrieve the ip address and store
perror("The problem was"); // at location ipstr
}

} else { // AF_INET6 this is the same as the above except it deals with IPv6 length
ipstr = malloc(INET6_ADDRSTRLEN);
struct sockaddr_in6 *s = (struct sockaddr_in6 *)&addr;
inet_ntop(AF_INET6, &s->sin6_addr, ipstr, sizeof(ipstr));
}
printf("%s",ipstr);
}

我遗漏了程序的其余部分,因为它太大了,我只想专注于修复这部分。但是,下面我将向您展示调用此函数的 main() 部分。

newSock = accept(listenSock,(struct sockaddr *)&their_addr,&addr_size);
char *someString;
getTheirIp(newSock,someString);

任何帮助都会很棒。谢谢!

最佳答案

inet_ntop(AF_INET, &s->sin_addr, ipstr, sizeof(ipstr))

sizeof 是错误的,因为 ipstr 是一个指针(它将产生指针的大小,类似于 4 8)。您需要传递 ipstr 缓冲区的可用长度。

关于c - inet_ntop : No space left on device,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9235798/

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