linux - 替换命令不起作用

Question

我想替换这段代码

 for($counter=0;$counter<10;$counter++)
 {
     $yyarr[$counter]=$counter+2004;
 }

与

 for($counter=2004;$counter<=date("Y");$counter++)
 {
     $yyarr[$counter-2004]=$counter;
 }

我正在使用

sed -e 's/for\(\$counter=0;\$counter<10;\$counter++\)\n\t+{\n\t+\$yyarr\[\$counter\]=\$counter+2004;\n\t+}/for\(\$counter=2004;\$counter<=date\("Y"\);\$counter++\)\n{\$yyarr\[\$counter-2004\]=\$counter;\n}/g'

但是打不开。尾随空格需要被忽略。

Answer 1

sed ':a;N;$!ba;s/for($counter=0;$counter<10;$counter++)\n{\n    $yyarr\[$counter\]=$counter+2004;\n}/for($counter=2004;$counter<=date("Y");$counter++)\n{\n    $yyarr\[$counter-2004\]=$counter;\n}/g' file

您遇到换行问题 \n。上面的代码将修复它。