linux - 字符串操作 : remove last component of path

Question

这是我的代码

real_path="/u1/h7/user/469/code/hw4/b.sh"
while [ "$real_path" != "/" ]
do
  echo $real_path
  real_path=${real_path%/*}
done
echo $real_path   #just to print the root '/' 

我希望我的脚本打印以下行，但 real_path=${real_path%/*} 似乎不起作用，有任何建议或其他方式来实现吗？

/u1/h7/user/469/code/hw4/b.sh
/u1/h7/user/469/code/hw4
/u1/h7/user/469/code
/u1/h7/user/469
/u1/h7/user
/u1/h7
/u1
/

Answer 1

您可以使用目录名:

#! /bin/bash

real_path="/u1/h7/user/469/code/hw4/b.sh"
while [ "$real_path" != "/" ];do
    echo "$real_path"
    real_path=$(dirname "$real_path")
done
echo "$real_path"

输出:

/u1/h7/user/469/code/hw4/b.sh
/u1/h7/user/469/code/hw4
/u1/h7/user/469/code
/u1/h7/user/469
/u1/h7/user
/u1/h7
/u1
/