iphone - 将 uint8_t 数组转换为 NSString

Question

如何将 uint8_t 数组(参见下面的 decryptedBuffer)影响到 NSString？

uint8_t *decryptedBuffer;

NSString *cle2=[NSString stringWithUTF8String:decryptedBuffer];

NSString *str2=[player.name AES256DecryptWithKey:cle2]; 
NSLog(str2);


free(plainBuffer);
free(cipherBuffer);
free(decryptedBuffer);

Answer 1

uint8_t * 只是一个与 char * 兼容的字节字符串，因此您应该能够将转换后的指针传递给 stringWithUTF8String，假设解密后的字符串是 UTF-8 并且以 NULL 结尾:

NSString *s = [NSString stringWithUTF8String:(char *)decryptedBuffer];

如果数据不是以NULL结尾，你可以这样使用:

NSString *s = [[[NSString alloc] initWithBytes:decryptedBuffer
                                 length:length_of_buffer
                                 encoding:NSUTF8StringEncoding] autorelease];