objective-c - NSInteger 到 8 位格式的二进制(字符串)值

Question

Jarret Hardie(谢谢!)昨天发布了这段代码，将 NSinteget 转换为二进制，并且运行良好，但我需要 8 位格式:

4 -> 00000100

修改此代码有什么想法吗？

// Original author Adam Rosenfield... SO Question 655792
NSInteger theNumber = 56;
NSMutableString *str = [NSMutableString string];
for(NSInteger numberCopy = theNumber; numberCopy > 0; numberCopy >>= 1)
{
    // Prepend "0" or "1", depending on the bit
    [str insertString:((numberCopy & 1) ? @"1" : @"0") atIndex:0];
}

NSLog(@"Binary version: %@", str);

谢谢!!!!!!

Answer 1

这应该有效:

NSInteger theNumber = 56;
NSMutableString *str = [NSMutableString string];
NSInteger numberCopy = theNumber; // so you won't change your original value
for(NSInteger i = 0; i < 8 ; i++) {
    // Prepend "0" or "1", depending on the bit
    [str insertString:((numberCopy & 1) ? @"1" : @"0") atIndex:0];
    numberCopy >>= 1;
}

NSLog(@"Binary version: %@", str);