objective-c - 使用 Objective-C 的 JSON 框架解析嵌套的 JSON 对象

Question

我有以下 JSON 对象:

{
"response": {
    "status": 200
},
"messages": [
    {
        "message": {
            "user": "value"
            "pass": "value",
            "url": "value"
         }
 ]
    }

我正在使用 JSON-Framework(也尝试过 JSON Touch)来解析它并创建一个字典。我想访问“消息” block 并提取“用户”、“传递”和“url”值。

在 Obj-C 中，我有以下代码:

// Create new SBJSON parser object
SBJSON *parser = [[SBJSON alloc] init];

// Prepare URL request to download statuses from Twitter
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:myURL]]; 

// Perform request and get JSON back as a NSData object
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

// Get JSON as a NSString from NSData response
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];

//Print contents of json-string
NSArray *statuses = [parser objectWithString:json_string error:nil];
NSLog(@"Array Contents: %@", [statuses valueForKey:@"messages"]);
NSLog(@"Array Count: %d", [statuses count]);


NSDictionary *results = [json_string JSONValue];
NSArray *tweets = [[results objectForKey:@"messages"] objectForKey:@"message"];

for (NSDictionary *tweet in tweets)
{
    NSString *url = [tweet objectForKey:@"url"];
    NSLog(@"url is: %@",url);
}

我可以提取“消息”并查看所有“消息” block ，但我无法更深入地解析并提取“用户”、“密码”和“url”。

Answer 1

已解决:

NSArray *tweets = [[results objectForKey:@"messages"] valueForKey:@"message"];