Python (Matplotlib) - 三元图上的刻度线

Question

我正在尝试在等边三角形的边上绘制看起来像刻度线的尖齿。我正在使用 Python 中的 Matplotlib 执行此操作。

这是等边三角形***:

import matplotlib.pyplot as plt
from pylab import *
fig = figure()
ax = fig.add_subplot(111)
ax.axis('equal')
ax.plot([1, 0.5], [0, 0.866], 'k-')
ax.plot([0, 0.5], [0, 0.866], 'k-')
ax.plot([0, 1], [0, 0], 'k-')
ax.plot([0.5, 1.01, 0.1], [-0.01, 0.5, 0.88], 'w.') #base boundary
plt.show()

生成的图像见此处。 .

现在，我想添加看起来像刻度线的线条。线条将像看到的那样绘制 here from 1:07-1:29 and from 2:19-2:32 .

我希望输出看起来像这张图片。

有没有办法用 Matplotlib 画这些线？

编辑:***三角代码根据here

Answer 1

这或多或少做了你想要的:

from __future__ import division
import matplotlib.pyplot as plt
import numpy as np

def plot_ticks(start, stop, tick, n):
    r = np.linspace(0, 1, n+1)
    x = start[0] * (1 - r) + stop[0] * r
    x = np.vstack((x, x + tick[0]))
    y = start[1] * (1 - r) + stop[1] * r
    y = np.vstack((y, y + tick[1]))
    plt.plot(x, y, 'k', lw=1)

n = 10
tick_size = 0.2
margin = 0.05

# define corners of triangle    
left = np.r_[0, 0]
right = np.r_[1, 0]
top = np.r_[0.5, 3**0.5 / 2]
triangle = np.c_[left, right, top, left]

# define vectors for ticks
bottom_tick = tick_size * (right - top) / n
right_tick = tick_size * (top - left) / n
left_tick = tick_size * (left - right) / n

plt.plot(triangle[0], triangle[1], 'k', lw=2) 
plot_ticks(left, right, bottom_tick, n)
plot_ticks(right, top, right_tick, n)
plot_ticks(left, top, left_tick, n)
plt.axis([left[0]-margin, right[0]+margin, left[1]-margin, top[1]+margin])
plt.gca().set_aspect('equal', adjustable='box')
plt.show()    

结果: