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python - 对词典列表进行排序和分组

转载 作者:太空狗 更新时间:2023-10-30 02:56:18 25 4
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我如何将这个字典列表排序和分组到一个嵌套字典中,我想通过 API 作为 JSON 返回它。

源数据(权限列表):

[{
'can_create': True,
'can_read': True,
'module_name': 'ModuleOne',
'module_id': 1,
'role_id': 1,
'end_point_id': 1,
'can_update': True,
'end_point_name': 'entity',
'can_delete': True,
}, {
'can_create': True,
'can_read': True,
'module_name': 'ModuleTwo',
'module_id': 2,
'role_id': 1,
'end_point_id': 4,
'can_update': True,
'end_point_name': 'financial-outlay',
'can_delete': True,
},{
'can_create': True,
'can_read': True,
'module_name': 'ModuleOne',
'module_id': 1,
'role_id': 1,
'end_point_id': 2,
'can_update': True,
'end_point_name': 'management-type',
'can_delete': True,
}, {
'can_create': True,
'can_read': True,
'module_name': 'ModuleOne',
'module_id': 1,
'role_id': 1,
'end_point_id': 3,
'can_update': True,
'end_point_name': 'ownership-type',
'can_delete': False,
}, {
'can_create': True,
'can_read': True,
'module_name': 'ModuleTwo',
'module_id': 2,
'role_id': 1,
'end_point_id': 5,
'can_update': True,
'end_point_name': 'exposure',
'can_delete': True,
}]

我想将其转换为嵌套的字典对象,以便通过 API 作为 JSON 返回。这是预期的输出:

{
"role_id": 1,
"modules": [{
"module_id": 1,
"module_name": "ModuleOne",
"permissions": [{
"end_point_id": 1,
"end_point_name": "entity",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, {
"end_point_id": 2,
"end_point_name": "management-type",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, {
"end_point_id": 3,
"end_point_name": "ownership-type",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, ]
}, {
"module_id": 2,
"module_name": "ModuleTwo",
"permissions": [{
"end_point_id": 4,
"end_point_name": "financial-outlay",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, {
"end_point_id": 5,
"end_point_name": "exposure",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, ]
},

]
}

它看起来微不足道,直到我花了更多的时间来尝试绕过它。我尝试了很多选择,但没有一个起作用。这是最后一次尝试。

# Get user role
user_roles = get_user_roles() # List of roles e.g. [{'role_id':1, role_name: 'role_one'}, {'role_id':2, role_name: 'role_two'}]

for role in user_roles:
role_id = role['role_id']
role_name = role['role_name']

# Fetch Role Permissions
role_permissions = get_role_permissions(role_id) # List of permissions as seen above
sorted_role_permissions = sorted(role_permissions, key=itemgetter('module_id')) # sort dictionaries in list by 'module_id'

modules_list = []
permissions_list = []
previous_module_id = 0
is_first_loop = True
for role_permission in sorted_role_permissions:

module_id = role_permission['module_id']
module_name = role_permission['module_name']
end_point_id = role_permission['end_point_id']
end_point_name = role_permission['end_point_name']

if is_first_loop:
print(0)
is_first_loop = False
previous_module_id = module_id
print('end_point_name 0 {}'.format(end_point_name))
permissions = {'end_point_id': end_point_id, 'end_point_name': end_point_name,
'can_create': role_permission['can_create'],
'can_read': role_permission['can_read'],
'can_update': role_permission['can_update'],
'can_delete': role_permission['can_delete']
}
permissions_list.append(permissions)
if len(sorted_role_permissions) == 1:
# If there is only one permission in the role, end the loop
modules_dict = {'module_id': module_id, 'module_name': module_name,
'permissions': permissions_list}
modules_list.append(modules_dict)
break

else:

if module_id == previous_module_id:
# As long as the current module_id and the previous_module_id are the same, add to the same list

print(1)
permissions = {'end_point_id': end_point_id, 'end_point_name': end_point_name,
'can_create': role_permission['can_create'],
'can_read': role_permission['can_read'],
'can_update': role_permission['can_update'],
'can_delete': role_permission['can_delete']
}
permissions_list.append(permissions)

else:

print(2)
modules_dict = {'module_id': module_id, 'module_name': module_name,
'permissions': permissions_list}
modules_list.append(modules_dict)
permissions_list = []
permissions = {'end_point_id': end_point_id, 'end_point_name': end_point_name,
'can_create': role_permission['can_create'],
'can_read': role_permission['can_read'],
'can_update': role_permission['can_update'],
'can_delete': role_permission['can_delete']
}
permissions_list.append(permissions)
previous_module_id = module_id

if modules_list:
roles.append({'role_id': role_id, 'role_name': role_name, 'modules': modules_list})

最佳答案

多田!

from itertools import groupby

def group_by_remove(permissions, id_key, groups_key, name_key=None):
"""
@type permissions: C{list} of C{dict} of C{str} to C{object}
@param id_key: A string that represents the name of the id key, like "role_id" or "module_id"
@param groups_key: A string that represents the name of the key of the groups like "modules" or "permissions"
@param name_key: A string that represents the name of the key of names like "module_name" (can also be None for no names' key)
"""
result = []
permissions_key = lambda permission: permission[id_key]
# Must sort for groupby to work properly
sorted_permissions = sorted(permissions, key=permissions_key)
for key, groups in groupby(sorted_permissions, permissions_key):
key_result = {}
groups = list(groups)
key_result[id_key] = key
if name_key is not None:
key_result[name_key] = groups[0][name_key]
key_result[groups_key] = [{k: v for k, v in group.iteritems() if k != id_key and (name_key is None or k != name_key)} for group in groups]
result.append(key_result)
return result

def change_format(initial):
"""
@type initial: C{list}
@rtype: C{dict} of C{str} to C{list} of C{dict} of C{str} to C{object}
"""
roles_group = group_by_remove(initial, "role_id", "modules")[0]
roles_group["modules"] = group_by_remove(roles_group["modules"], "module_id", "permissions", "module_name")
return roles_group

change_format(role_permissions)

享受 :)

关于python - 对词典列表进行排序和分组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39989777/

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