python - 解码 json 时出现 ValueError

Question

import json
import urllib
import re
import binascii 

def asciirepl(match):
  s = match.group()  
  return binascii.unhexlify(s[2:])  

query = 'google'
p = urllib.urlopen('http://www.google.com/dictionary/json?callback=a&q='+query+'&sl=en&tl=en&restrict=pr,de&client=te')
page = p.read()[2:-10] #As its returned as a function call

#To replace hex characters with ascii characters
p = re.compile(r'\\x(\w{2})')
ascii_string = p.sub(asciirepl, page)

#Now decoding cleaned json response
data = json.loads(ascii_string)

运行它，我得到这个错误，

shadyabhi@archlinux /tmp $ python2 define.py                                                                                                                                      
Traceback (most recent call last):
  File "define.py", line 19, in <module>
    data = json.loads(ascii_string)
  File "/usr/lib/python2.7/json/__init__.py", line 326, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python2.7/json/decoder.py", line 366, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/lib/python2.7/json/decoder.py", line 382, in raw_decode
    obj, end = self.scan_once(s, idx)
ValueError: Expecting , delimiter: line 1 column 403 (char 403)

据我所知，json 没有任何错误，因为我从谷歌的服务器收到了它。我所做的只是删除十六进制字符。任何帮助将不胜感激。

Answer 1

解码\x 转义可能会产生 "标记，当它们出现在 JSON 数据中编码的“字符串”中时，需要重新转义。

def asciirepl(match):
  chr = binascii.unhexlify(match.group()[2:])
  return '\\' + chr if chr in ('\\"') else chr

那仍然不能处理控制字符；因此您可能希望将\x 转义符转换为\u 转义符，这在 JSON 标准中有描述并由 json 模块解析。这具有更简单的附带好处:)

def asciirepl(match):
  return '\\u00' + match.group()[2:]