python - 使用python smtplib发送邮件错误

Question

我正在尝试使用 python 3.2 SMTPlib.sendmail() 函数在对 SMTP 库(即注释掉抑制错误消息的 rset() 函数)我设法从服务器检索到以下错误消息:

发送邮件失败(554，b'交易失败:由于可能滥用而无法发送消息；请访问 http://postmaster.yahoo.com/abuse_smtp.html 了解更多信息')

雅虎邮件 SMTP 服务器认为我在发送垃圾邮件，该 URL 确实链接到任何东西有用。我认为这与 header 不足有关，我似乎找不到明确的回答什么是合规 header &我读过 Gmail 的类似问题。模拟电子邮件已替换此帖子。

任何帮助将不胜感激

我的完整代码如下:

    self.message =  email.message_from_string('''To: <ksmith@yahoo.co.nz>
    From: <rwilson@yahoo.co.nz>
    Reply-To: <rwilson@yahoo.co.nz>
    Subject: Test send mail \n\n Hello''')
    fromAddress = 'rwilson@yahoo.co.nz'
    toAddress = 'ksmith@yahoo.co.nz'
    try:
        self.smtp = SMTP()
        self.smtp.connect('smtp.mail.yahoo.com')
    except Exception:
        print('Connection Failed')
        print(traceback.format_exc())
    try:
        self.smtp.login('rwilson','tree22')
    except Exception:
        print('Login Failed!')
        print(traceback.format_exc())
    try:
        self.smtp.sendmail(fromAddress,toAddress ,self.message.as_string())
        print("Message sucessfully sent!")
        self.smtp.close()
    except Exception as e:
        print('SendMail Failed')
        print(e)

Answer 1

以下适用于 Python 2.7 和 Python 3.2 上的 Microsoft、google、yahoo 帐户:

#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Send email via smtp_host."""
import smtplib
from email.mime.text import MIMEText
from email.header    import Header

####smtp_host = 'smtp.live.com'        # microsoft
####smtp_host = 'smtp.gmail.com'       # google
smtp_host = 'smtp.mail.yahoo.com'  # yahoo
login, password = ...
recipients_emails = [login]

msg = MIMEText('body…', 'plain', 'utf-8')
msg['Subject'] = Header('subject…', 'utf-8')
msg['From'] = login
msg['To'] = ", ".join(recipients_emails)

s = smtplib.SMTP(smtp_host, 587, timeout=10)
s.set_debuglevel(1)
try:
    s.starttls()
    s.login(login, password)
    s.sendmail(msg['From'], recipients_emails, msg.as_string())
finally:
    s.quit()